Question:

<p><strong>1</strong>: Let x = \lambda + h. As x \to \lambda, h \to 0.</p><p><strong>2</strong>: Base = 2 -</p> \lambda \lambda+h = 2\lambda+2h-\lambda \lambda+h = \lambda+2h \lambda+h = 1 + h \lambda+h \approx1 + h \lambda.<p><strong>3</strong>: Exponent \lambda tan</p>  \pi(\lambda+h) 2\lambda  = \lambda tan(\pi/2 + \pih/2\lambda) = -\lambda cot(\pih 2\lambda) \approx-2\lambda2 \pih .<p><strong>4</strong>: Limit = elimh\to 0 h</p> \lambda  -2\lambda2 \pih  = e-2\lambda/\pi.<p><strong>5</strong>: Given e-2\lambda/\pi = e-1 =\Rightarrow </p> 2\lambda \pi = 1 =\Rightarrow \lambda = \pi/2.