Definite Integration
Integration of trigonometric functions
Grade Class 12

Question:

For x &isin; (-&pi;/2, &pi;/2), if y(x) = &int; (cosec x + sin x) / (cosec x sec x + tan x sin<sup>2</sup> x) dx and lim <sub>x&rarr;&pi;/2</sub> y(x) = 0 then y(&pi;/4) is equal to
tan<sup>-1</sup>(1/&radic;2)
1/2 tan<sup>-1</sup>(1/&radic;2)
-1/&radic;2 tan<sup>-1</sup>(1/&radic;2)
1/&radic;2 tan<sup>-1</sup>(-1/2)

Step-by-Step Solution

Key Concept: Simplify the integrand by converting to sin and cos, then use substitution.
The integrand is (1/sin x + sin x) / (1/(sin x cos x) + sin x tan<sup>2</sup> x) = (1+sin<sup>2</sup> x)/sin x / (1/(sin x cos x) + sin<sup>3</sup> x/cos x) = (1+sin<sup>2</sup> x)/sin x * (sin x cos x) / (1+sin<sup>4</sup> x) = (cos x (1+sin<sup>2</sup> x)) / (1+sin<sup>4</sup> x). Let sin x = t, then cos x dx = dt. The integral becomes &int; (1+t<sup>2</sup>) / (1+t<sup>4</sup>) dt = &int; (1+1/t<sup>2</sup>) / (t<sup>2</sup>+1/t<sup>2</sup>) dt = &int; d(t-1/t) / ((t-1/t)<sup>2</sup>+2) = 1/&radic;2 tan<sup>-1</sup>((t-1/t)/&radic;2) + C. Using the limit condition, find C and evaluate at x=&pi;/4.
Correct Answer: 4

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