Binomial Theorem
Constant Term — Finding Parameter
nta_pyq_2024_apr
Grade 11

Question:

If the constant term in the expansion of $\left(\dfrac{5\sqrt[3]{x}}{\sqrt{x}}+\dfrac{2x}{\sqrt[3]{5x}}\right)^{12}$, $x\neq0$, is $\alpha\times2^8\times\sqrt[3]{5}$, then $25\alpha$ is equal to:
724
742
639
693

Step-by-Step Solution

Key Concept: Simplify each term, find $r$ for zero power of $x$, compute constant term coefficient.
$25\alpha=693$.
Correct Answer: 4

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