Matrices & Determinants
General
Grade 12
Question:
If $A, B$ are two matrices such that $A + B = \begin{bmatrix} 1 & 2 \\ 2 & 4 \end{bmatrix}, A - B = \begin{bmatrix} 3 & 2 \\ -2 & 0 \end{bmatrix}$, then find $AB$.
Step-by-Step Solution
Key Concept: General
Given $A + B = \begin{bmatrix} 1 & 2 \\ 2 & 4 \end{bmatrix}$ ...(i) & $A - B = \begin{bmatrix} 3 & 2 \\ -2 & 0 \end{bmatrix}$ ...(ii). Adding (i) & (ii): $2A = \begin{bmatrix} 4 & 4 \\ 0 & 4 \end{bmatrix} \Rightarrow A = \begin{bmatrix} 2 & 2 \\ 0 & 2 \end{bmatrix}$. Subtracting (ii) from (i): $2B = \begin{bmatrix} -2 & 0 \\ 4 & 4 \end{bmatrix} \Rightarrow B = \begin{bmatrix} -1 & 0 \\ 2 & 2 \end{bmatrix}$. Now, $AB = \begin{bmatrix} 2 & 2 \\ 0 & 2 \end{bmatrix} \begin{bmatrix} -1 & 0 \\ 2 & 2 \end{bmatrix} = \begin{bmatrix} -2 + 4 & 0 + 4 \\ 0 + 4 & 0 + 4 \end{bmatrix} = \begin{bmatrix} 2 & 4 \\ 4 & 4 \end{bmatrix}$.
Correct Answer: $\begin{bmatrix} 2 & 4 \\ 4 & 4 \end{bmatrix}$