Statistics
Corrected Variance — Single Wrong Observation
nta_pyq_2023_apr
Grade 11

Question:

Mean and SD of 10 observations are 20 and 8. One observation was recorded as 50 instead of 40. Then the correct variance is
11
13
12
14

Step-by-Step Solution

Key Concept: Correct $\sum x_i=200-50+40=190$. New mean $=19$. Correct $\sum x_i^2=10(64+400)-2500+1600=4640-900=3740$. Variance $=\frac{3740}{10}-361=374-361=13$.
Correct variance $=13$.
Correct Answer: 2

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