Coordinate Geometry
CH07 Question Bank
CBSE_CH07_QUESTION_BANK
Grade 10
Question:
Find the value(s) of $y$ for which the distance between the points $(2,y)$ and $(10,-3)$ is $10$ units.
Step-by-Step Solution
Key Concept: Set up the distance formula equation and solve for y.
$\sqrt{64+(y+3)^2}=10\Rightarrow(y+3)^2=36$. [1.0 Mark]
$y+3=\pm6\Rightarrow y=3$ or $y=-9$. [1.0 Mark]
Correct Answer:
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