Question:

If $\alpha,\beta,\gamma$ are the roots of $x^3+ax^2+bx+c=0$ and $\alpha+\beta=0$, then

$ab=c$

$a^2b^2=c^2$

$a^2b-ab^2=c^2$

$a^2b=c$... (match condition)

Step-by-Step Solution

Key Concept: $\alpha+\beta+\gamma=-a$; $\alpha+\beta=0\Rightarrow\gamma=-a$; use Vieta's

$ab=c$.

Correct Answer: 4