Limits, Continuity & Differentiability
General
Grade 12
Question:
<p>limn→∞
1+2−3+···+(3n−2)+(3n−1)−3n
√
2n4+4n+3−
√
n4+5n+4</p>
Step-by-Step Solution
Key Concept: General
<p>Numerator \approx1.5n2. Denom \approx(</p> \sqrt 2 -1)n2. Ratio = 1.5( \sqrt 2 + 1) = 3 2( \sqrt 2 + 1). Option (3).
Correct Answer: (3)