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Introduction to Trigonometry

CH08 Question Bank

CBSE_CH08_QUESTION_BANK

Grade 10

Question:

If $\cot\theta=\dfrac{5}{12}$, the value of $\text{cosec}^2\theta$ is:

$\dfrac{25}{144}$
$\dfrac{169}{144}$
$\dfrac{144}{169}$
$\dfrac{13}{12}$

Step-by-Step Solution

Key Concept: Apply the identity $1+\cot^2\theta=\text{cosec}^2\theta$.

$\text{cosec}^2\theta=1+\cot^2\theta=1+\dfrac{25}{144}=\dfrac{169}{144}$. [1.0 Mark]

Correct Answer: $\dfrac{169}{144}$

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