Quadratic Equations Question - CBSE_NCERT_EXEMPLAR_CH04

Question

The quadratic equation $2x^2 - \sqrt{5}x + 1 = 0$ has:

Two distinct real roots
Two equal real roots
No real roots
More than 2 real roots

Accepted Answer

Stepwise Solution:

Here $a=2, b=-\sqrt{5}, c=1$. $D = (-\sqrt{5})^2 - 4(2)(1) = 5 - 8 = -3$. [0.5 Mark]

Since $D = -3 < 0$, the quadratic equation has no real roots. [0.5 Mark]

Marking Scheme:

• Calculating $D = -3$: 0.5 Mark
• Deducing no real roots since $D < 0$: 0.5 Mark

Question:

Step-by-Step Solution

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