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Coordinate Geometry
Ellipse, Eccentricity
jee_main_2026_april_8_shift_2
Grade None

Question:

The eccentricity of the ellipse x²/64 + y²/28 = 1 is:
A. 1/2
B. 3/4
C. 5/6
D. 7/8

Step-by-Step Solution

Key Concept: Ellipse eccentricity: e = √(1 - b²/a²).
Step 1: a² = 64, b² = 28. Step 2: e = √(1 - 28/64) = √(36/64) = 6/8 = 3/4.
Correct Answer: B
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