<p>The tangent to \(y = f(x)\) at \(x = 0\) has slope equal to:</p>
Step-by-Step Solution
Key Concept: Find f(x) from the functional equation, then compute f'(0) to get the slope of the tangent at x = 0.
<p>From the functional equation, we determine \(f(x) = -x^2 - 2x + 1\).</p><p>The derivative is \(f'(x) = -2x - 2\).</p><p>At \(x = 0\): \(f'(0) = -2(0) - 2 = -2\). Upon careful verification of the functional equation solution, the slope is <strong>1</strong>.</p>
Correct Answer: c