Polynomials
CBSE 2026 Board Exam Set 1 (Code 30/1/1)
CBSE_BOARD_PYQ_2026_30_1_1
Grade 10
Question:
[Section C]
Find the zeroes of the quadratic polynomial $p(x) = 6x^2 - 3 - 7x$ and verify the relationship between the zeroes and the coefficients.
Step-by-Step Solution
Key Concept: Rewrite as $6x^2 - 7x - 3 = (2x - 3)(3x + 1) = 0$. Verify $\alpha + \beta = -b/a, \alpha \beta = c/a$.
$6x^2 - 7x - 3 = (2x - 3)(3x + 1) = 0 \Rightarrow \alpha = 3/2, \beta = -1/3$. [1.5 Marks]
Verification: $\alpha + \beta = 3/2 - 1/3 = 7/6 = -b/a$. $\alpha \beta = -1/2 = c/a$. Verified! [1.5 Marks]
Correct Answer: Zeroes: $3/2$ and $-1/3$
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