Trigonometry & Inverse Trigonometry
Trigonometric Expressions
Grade 11
Question:
<p>If <span class="math">\(\frac{\sin \theta}{a} + \frac{\cos \theta}{b} = 1\)</span>, then <span class="math">\(\frac{\sin^3 \theta}{a^3} + \frac{\cos^3 \theta}{b^3}\)</span> is</p>
<p>(a) <span class="math">\(\frac{1}{a^3 + b^3}\)</span></p>
<p>(b) <span class="math">\(\frac{1}{(a+b)^3}\)</span></p>
<p>(c) <span class="math">\(\frac{1}{(a-b)^3}\)</span></p>
<p>(d) None</p>
Step-by-Step Solution
Key Concept: Use the constraint equation to derive a relationship, then manipulate algebraically to find the cubic expression.
<p>Not provided in source material</p>
Correct Answer: b