Area Under the Curve
Area = 2 (integer)
Grade 12
Question:
<p>Area bounded by \(y=\sqrt{x}\) and \(y=x^2\) on \([0,1]\). [JEE Main 2022]</p>
Step-by-Step Solution
Key Concept: \int_0^1(\sqrt{x} - x^2)dx = 2/3 - 1/3 = 1/3.
<div class='solution'><p>$$\int_0^1(\sqrt{x}-x^2)dx=\frac{2}{3}-\frac{1}{3}=\frac{1}{3}$$</p></div>
Correct Answer: A