Complex Numbers
Roots of Unity and Orthogonality
Grade 11
Question:
<p>Let <i>w</i> = e<sup>iπ/3</sup>, where <i>i</i> = √−1 and <i>a</i>, <i>b</i>, <i>c</i>, <i>x</i>, <i>y</i> and <i>z</i> be non-zero complex numbers such that</p><p>a + b + c = x</p><p>a + <i>b</i>ω + <i>c</i>ω² = <i>y</i></p><p>a + <i>b</i>ω² + <i>c</i>ω = <i>z</i></p><p>The value of \(\frac{|x|^2 + |y|^2 + |z|^2}{|a|^2 + |b|^2 + |c|^2}\) is</p>
Step-by-Step Solution
Key Concept: The transformation matrix involving cube roots of unity is orthogonal (up to scaling), so Parseval's identity applies directly.
<p><strong>Step 1:</strong> The system of equations can be written in matrix form as:</p><p>$$\begin{pmatrix} 1 & 1 & 1 \\ 1 & \omega & \omega^2 \\ 1 & \omega^2 & \omega \end{pmatrix} \begin{pmatrix} a \\ b \\ c \end{pmatrix} = \begin{pmatrix} x \\ y \\ z \end{pmatrix}$$</p><p><strong>Step 2:</strong> The matrix is a DFT-type matrix with ω = e^(2πi/3), and its rows are orthogonal.</p><p><strong>Step 3:</strong> By Parseval's theorem (or orthogonality of DFT), $|x|^2 + |y|^2 + |z|^2 = 3(|a|^2 + |b|^2 + |c|^2)$.</p><p>∴ The value is <strong>3</strong>.</p>
Correct Answer: 3