Coordinate Geometry
Circle
MMTS_Full_Test_03
Grade 12
Question:
The equation of a circle passing through origin, making equal intercepts on coordinate axes and passing through $(4,3)$ is
$x^2+y^2-7x-7y=0$
$x^2+y^2+6x+6y=0$
$x^2+y^2-14x-14y=0$
None of these
Step-by-Step Solution
Key Concept: Equal intercepts: centre at $(a,a)$; passes through origin: $r^2=2a^2$; passes through $(4,3)$
$a=25/14$. Equation: $x^2+y^2-\frac{25}{7}x-\frac{25}{7}y=0$. None of given options (option 4).
Correct Answer: 1