Vectors b = (tan α, −1, 2 sin α/2) and c = (tan α, tan α, −3 sin α/2) are orthogonal and vectors a = (1, 3, sin 2α) makes an obtuse angle with the Z-axis, then the value of α is
[JEE Main 2020] Let \(\vec{a},\vec{b},\vec{c}\) be three vectors such that \(\vec{a}\neq\vec{0},\;|\vec{b}|=4,\;|\vec{c}|=2\). Given \(\vec{a}=\vec{b}\times(2\vec{a}+\lambda\vec{c})\), \(\lambda>0\). If angle between \(\vec{b}\) and \(\vec{c}\) is \(\pi/3\) and \((\vec{a}\times\vec{b})\cdot\vec{c}=|\vec{a}|\), then \(\lambda\) equals
Let a vector \(\hat{i}+\sqrt{2}\,\hat{j}+\sqrt{2}\,\hat{k}\) be obtained by rotating the vector \(\sqrt{3}\,\hat{j}\) by an angle \(45°\) about the origin in the clockwise direction to the first quadrant. Then the area of the triangle formed by the vector \((\hat{i}+\sqrt{2}\,\hat{j}+\sqrt{2}\,\hat{k})\) with the coordinate axes is equal to:
[JEE Main 2020] Let \(\vec{a},\vec{b},\vec{c}\) be three vectors such that \(\vec{a}\neq\vec{0},\;|\vec{b}|=4,\;|\vec{c}|=2\). Given \(\vec{a}=\vec{b}\times(2\vec{a}+\lambda\vec{c})\), \(\lambda>0\). If angle between \(\vec{b}\) and \(\vec{c}\) is \(\pi/3\) and \((\vec{a}\times\vec{b})\cdot\vec{c}=|\vec{a}|\), then \(\lambda\) equals
Four points \(A(1,-1,1),\;B(3,1,1),\;C(6,3,1)\) and \(D(6,-1,-1)\) taken in order are the vertices of