Let $\vec{a}=2\hat{i}+\alpha\hat{j}+\hat{k}$, $\vec{b}=-\hat{i}+\hat{k}$, $\vec{c}=\beta\hat{j}-\hat{k}$, where $\alpha$ and $\beta$ are integers and $\alpha\beta=-6$. Let the values of the ordered pair $(\alpha,\beta)$, for which the area of the parallelogram of diagonals $\vec{a}+\vec{b}$ and $\vec{b}+\vec{c}$ is $\dfrac{\sqrt{21}}{2}$, be $(\alpha_1,\beta_1)$ and $(\alpha_2,\beta_2)$. Then $\alpha_1^2+\beta_1^2-\alpha_2\beta_2$ is equal to
If $A(3,1,-1)$, $B\left(\dfrac{5}{3},\dfrac{7}{3},\dfrac{1}{3}\right)$, $C(2,2,1)$ and $D\left(\dfrac{10}{3},\dfrac{2}{3},-\dfrac{1}{3}\right)$ are the vertices of a quadrilateral $ABCD$, then its area is
In an isosceles triangle \(ABC\) with \(AB=AC\), M is the midpoint of \(BC\). Given an equilateral triangle with side \(\vec{a}\), the scalar triple product \([\vec{a},\vec{b},\vec{c}]\) (where \(\vec{a},\vec{b},\vec{c}\) are sides) equals
Ex. 55 Let A, B, C, D, E represent vertices of a regular pentagon ABCDE with position vectors \(\vec{a}, \vec{a} + \vec{b}, \vec{b}, \lambda \vec{a}, \lambda \vec{b}\) respectively. The ratio \(\frac{AD}{BC}\) is equal to
The points A(2-x, 2, 2), B(2, 2-y, 2), C(2, 2, 2-z) and D(1, 1, 1) are coplanar. Find the locus of P(x, y, z).