Algebra Questions (626)

Given two vectors are \(\hat{i} - \hat{j}\) and \(\hat{i} + 2\hat{j}\) the unit vector coplanar with the two vectors and perpendicular to first is
A particle acted on by constant forces \(4\hat{i}+\hat{j}-3\hat{k}\) and \(3\hat{i}+\hat{j}-\hat{k}\) is displaced from the point \(\hat{i}+2\hat{j}+3\hat{k}\) to the point \(5\hat{i}+4\hat{j}+\hat{k}\). The total work done by the forces is
If \((\vec{a}\times\vec{b})\times\vec{c} = \vec{a}\times(\vec{b}\times\vec{c})\), where \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) are any three vectors such that \(\vec{a}\cdot\vec{b}\neq 0\), \(\vec{b}\cdot\vec{c}\neq 0\), then \(\vec{a}\) and \(\vec{c}\) are
For a non-zero vector \(\mathbf{a}\), the set of real numbers satisfying \(|(5-x)\mathbf{a}|
Let \(\vec{a},\, \vec{b},\, \vec{c}\) be three vectors of magnitude 2, 3, 5 respectively, satisfying \(|[\vec{a},\, \vec{b},\, \vec{c}]| = 30\). If \((2\vec{a} + \vec{b} + \vec{c}) \cdot ((\vec{a} \times \vec{c}) \times (\vec{a} - \vec{c}) + \vec{b}) = k\), then the value of \(\left(\dfrac{k}{103}\right)\) is:
If \(\vec{a}, \vec{b}, \vec{c}\) are non-coplanar vectors and \(\lambda\) is a real number, then the vectors \(\vec{a} + 2\vec{b} + 3\vec{c}\), \(\lambda\vec{b} + 4\vec{c}\) and \((2\lambda - 1)\vec{c}\) are non-coplanar for
If the vectors \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) from the sides \(BC\), \(CA\) and \(AB\), respectively, of a triangle \(ABC\), then
Let \(\vec{a}\) and \(\vec{b}\) be two unit vectors such that \(|\vec{a}+\vec{b}|=\sqrt{3}\). If \(\vec{c}=\vec{a}+2\vec{b}+3(\vec{a}\times\vec{b})\), then \(2|\vec{c}|\) is equal to
Ex. 62: Let ABC be a triangle whose centroid is G, orthocentre is H and circumcentre is the origin 'O'. If D is any point in the plane of the triangle such that no three of O, A, C and D are collinear satisfying the relation \(\vec{AD} + \vec{BD} + \vec{CH} + 3\vec{HG} = \lambda \vec{HD}\), then what is the value of the scalar \(\lambda\)?
64. Let \(\vec{\alpha} = 3\hat{i} + \hat{j}\) and \(\vec{\beta} = 2\hat{i} - \hat{j} + 3\hat{k}\). If \(\vec{\beta} = \vec{\beta}_1 - \vec{\beta}_2\), where \(\vec{\beta}_1\) is parallel to \(\vec{\alpha}\) and \(\vec{\beta}_2\) is perpendicular to \(\vec{\alpha}\), then \(\vec{\beta}_1 \times \vec{\beta}_2\) is equal to:
If \(|\vec{a}| = 1\), \(|\vec{b}| = 3\) and \(|\vec{c}| = 5\), then the value of \([\vec{a} - \vec{b}, \vec{b} - \vec{c}, \vec{c} - \vec{a}]\) is
Both the lines pass through origin. Line L1 is parallel to the vector \(\vec{V}_1 = (\cos\theta + \sqrt{3})\,\hat{i} + (\sqrt{2}\sin\theta)\,\hat{j} + (\cos\theta - \sqrt{3})\,\hat{k}\) and L2 is parallel to the vector \(\vec{V}_2 = a\hat{i} + b\hat{j} + c\hat{k}\) If the angle \(\alpha\) between the lines is independent of \(\theta\), find \(\alpha\).
Given 59. \(\vec{a} = \hat{i} + \hat{j} + \hat{k},\ \vec{c} = \hat{j} - \hat{k},\ \vec{a} \cdot \vec{b} = 3\) and \(\vec{a} \times \vec{b} = \vec{c}\), find \(|\vec{b}|\).
Given \(\vec{\alpha} = 3\hat{i} + \hat{j}\), \(\vec{\beta} = 2\hat{i} - \hat{j} + 3\hat{k}\). If \(\vec{\beta} = \vec{\beta}_1 - \vec{\beta}_2\) and \(\vec{\beta}_1\) is parallel to \(\vec{\alpha}\) and \(\vec{\beta}_2\) is perpendicular to \(\vec{\alpha}\), then \(\vec{\beta}_1 \times \vec{\beta}_2\) is equal to
If a = 3i - 2j + k, b = 2i - 4j - 3k and c = -i + 2j + 2k, then a + b + c is
Ex. 63: Let a, b and c be unit vectors such that \(\vec{a} + \vec{b} - \vec{c} = \vec{0}\). If the area of triangle formed by vectors \(\vec{a}\) and \(\vec{b}\) is A, then what is the value of \(16A^2\)?
The moment about the point \(\vec{i} + 2\vec{j} + 3\vec{k}\) of a force represented by \(\vec{i} + \vec{j} + \vec{k}\) acting through the point \(2\vec{i} + 3\vec{j} + \vec{k}\), is
Example 30. The median AD of the △ABC is bisected at E. BE meets AC in F. Then, AF : AC is equal to
Consider the set of eight vectors V = {ai + bj + ck : a, b, c ∈ {−1, 1}}. Three non-coplanar vectors can be chosen from V in \(2^p\) ways. Then p is ________.
A couple is of moment \(\vec{G}\) and the force forming the couple is \(\vec{P}\). If \(\vec{P}\) is turned through a right angle, the moment of the couple thus formed is \(\vec{H}\). If instead, the forces \(\vec{P}\) are turned through an angle \(\alpha\), then the moment of couple becomes
If |a| = |b| = |c| = 2 and \(\mathbf{a} \cdot \mathbf{b} = \mathbf{b} \cdot \mathbf{c} = \mathbf{c} \cdot \mathbf{a} = 2\), then \([\mathbf{a} \mathbf{b} \mathbf{c}] \cos 45°\) is equal to:
If C is the midpoint of AB and P is any point outside AB, then
Given \(\vec{a} = \hat{i} + \hat{j} + \sqrt{2}\hat{k}\), \(\vec{b} = b_1\hat{i} + b_2\hat{j} + \sqrt{2}\hat{k}\) and \(\vec{c} = 5\hat{i} + \hat{j} + \sqrt{2}\hat{k}\). Projection of \(\vec{b}\) on \(\vec{a}\) is \(|\vec{a}|\) and \((\vec{a}+\vec{b})\) is perpendicular to \(\vec{c}\). Find \(|\vec{b}|\).
Let a, b, c be unit vectors such that the Gram determinant \[\begin{vmatrix} \vec{a}\cdot\vec{a} & \vec{a}\cdot\vec{b} & \vec{a}\cdot\vec{c} \\ \vec{a}\cdot\vec{b} & \vec{b}\cdot\vec{b} & \vec{b}\cdot\vec{c} \\ \vec{a}\cdot\vec{c} & \vec{c}\cdot\vec{b} & \vec{c}\cdot\vec{c} \end{vmatrix} = [\vec{a}\;\vec{b}\;\vec{c}]^2 = 4.\] Find \([\vec{a}\;\vec{b}\;\vec{c}]\).
Let PQRS be a parallelogram whose diagonals \(\overrightarrow{PR}=3\hat{i}+\hat{j}\) and \(\overrightarrow{QS}=\hat{i}-\hat{j}+\hat{k}\). Find the area of PQRS.
[JEE Main 2019] Let \(\vec{a}=\hat{i}+2\hat{j}-\sqrt2\hat{k}\) and \(\vec{b}=\sqrt2\hat{i}-\hat{j}+\sqrt2\hat{k}\). If \(\vec{c}=\vec{a}\times(\vec{a}\times\vec{b})\), then \(|\vec{c}|\) equals
259. Given 2019 vectors on a plane. Sum of every 2018 vectors is a scalar multiple of other vector. Not all vectors are scalar multiple of each other. The magnitude of sum of all these vectors is:
Example 33. The vector \(\mathbf{c}\), directed along the internal bisector of the angle between the vectors \(\mathbf{a} = 7\mathbf{i} - 4\mathbf{j} - 4\mathbf{k}\) and \(\mathbf{b} = -2\mathbf{i} - \mathbf{j} + 2\mathbf{k}\) with \(|\mathbf{c}| = 5\sqrt{6}\), is
If the vector \(6\hat{i}-3\hat{j}-6\hat{k}\) is decomposed into vectors parallel and perpendicular to the vector \(\hat{i}+\hat{j}+\hat{k}\), then the two vectors are
If \(\vec{u}\), \(\vec{v}\) and \(\vec{w}\) are three non-coplanar vectors, then \((\vec{u}+\vec{v}-\vec{w})\cdot(\vec{u}-\vec{v})\times(\vec{v}-\vec{w})\) equals
Given \( \overrightarrow{OC} = m\overrightarrow{OA} + n\overrightarrow{OB} \), i.e., \( \vec{c} = m\vec{a} + n\vec{b} \), where \( |\vec{a}| = 1,\ |\vec{b}| = 1,\ |\vec{c}| = \sqrt{2},\ \tan\alpha = 7 \). Find the value of \( m + n \) (or the relevant expression as given in the problem).
If \(\hat{u}\) and \(\hat{v}\) are unit vectors and \(\theta\) is the acute angle between them, then \(2\hat{u}\times 3\hat{v}\) is a unit vector for
If \(|\vec{a}| = 2\), \(|\vec{b}| = 3\) and \(|2\vec{a} - \vec{b}| = 5\), then \(|2\vec{a} + \vec{b}|\) equals
Let \(\vec{a}\) and \(\vec{b}\) be two unit vectors and \(\theta\) is the angle between them. Then \(\vec{a} + \vec{b}\) is a unit vector, if
Let OA = a, OB = 10a + 2b and OC = b, where O, A and C are non-collinear points. Let p denote the area of quadrilateral OACB, and let q denote the area of parallelogram with OA and OC as adjacent sides. If p = kq, then k is equal to
Let \(\vec{a}=2\hat{i}-\hat{j}+\hat{k}\) and \(\vec{b}=\hat{i}+2\hat{j}-\hat{k}\). If \(\vec{c}=\alpha\vec{a}+\beta\vec{b}\) satisfies \(\vec{c}\times\vec{a}=\vec{b}\), find \(\alpha+\beta\).
Three forces \(\vec{P}\), \(\vec{Q}\) and \(\vec{R}\) acting along \(IA\), \(IB\) and \(IC\), where \(I\) is the incentre of a \(\triangle ABC\), are in equilibrium. Then \(\vec{P} : \vec{Q} : \vec{R}\) is
The resultant of two forces P N and 3 N is a force of 7 N. If the direction of 3 N force were reversed, the resultant would be \(\sqrt{19}\) N. The value of P is
The vectors \(\vec{a} = 2\lambda \vec{i} + 4\lambda \vec{j} + \vec{k}\) and \(\vec{b} = 7\vec{i} - 2\vec{j} + \lambda \vec{k}\) make an obtuse angle whereas the angle between \(\vec{b}\) and \(\vec{k}\) is acute and less than \(\pi/6\). Find the range of \(\lambda\).
In a triangle ABC, right-angled at the vertex A, if the position vectors of A, B and C are, respectively, \(3\hat{i}+\hat{j}-\hat{k}\), \(-\hat{i}+3\hat{j}+p\hat{k}\) and \(5\hat{i}+q\hat{j}-4\hat{k}\), then the point \((p, q)\) lies on a line
Let $\vec{a}=4\hat{i}-\hat{j}+\hat{k}$, $\vec{b}=11\hat{i}-\hat{j}+\hat{k}$ and $\vec{c}$ be a vector such that $(\vec{a}+\vec{b})\times\vec{c}=\vec{c}\times(-2\vec{a}+3\vec{b})$. If $(2\vec{a}+3\vec{b})\cdot\vec{c}=1670$, then $|\vec{c}|^2$ is equal to:
Let a = î + ĵ + k̂, b = î − ĵ + 2k̂ and c = xî + (x−2)ĵ − k̂. If the vector c lies in the plane of a and b, then x equals
[JEE Main 2021] Let \(\vec{a}=2\hat{i}+\hat{j}-2\hat{k}\) and \(\vec{b}=\hat{i}+\hat{j}\). Let \(\vec{c}\) be a vector such that \(\vec{a}\cdot\vec{c}=|\vec{c}|\), \(|\vec{c}-\vec{a}|=2\sqrt2\) and the angle between \(\vec{a}\times\vec{b}\) and \(\vec{c}\) is \(\dfrac\pi6\). Then \(|(\vec{a}\times\vec{b})\times\vec{c}|\) equals
Given \(\vec{a} = \hat{i} - \hat{j}\), \(\vec{b} = \hat{i} + \hat{j} + \hat{k}\), \(\vec{a} \times \vec{c} + \vec{b} = \vec{0}\) and \(\vec{a} \cdot \vec{c} = 4\). Find \(|\vec{c}|^2\).
For \(p>0\), the vector \(\vec{v}_2=(2,\,-(\sqrt{3}\,p+1))\) is obtained by rotating \(\vec{v}_1=\sqrt{3}(-1,\,-(p^2+\sqrt{3}))\) about the origin counter-clockwise. If the angle of rotation is \(\theta\), find \(\tan\theta\).
The resultant of forces \(\vec{P}\) and \(\vec{Q}\) is \(\vec{R}\). If \(\vec{Q}\) is doubled then \(\vec{R}\) is doubled. If the direction of \(\vec{Q}\) is reversed, then \(\vec{R}\) is again doubled. Then \(P^2 : Q^2 : R^2\) is
Let \(\hat{a}\) and \(\hat{b}\) be two unit vectors. If the vectors \(\vec{c} = \hat{a} + 2\hat{b}\) and \(\vec{d} = 5\hat{a} - 4\hat{b}\) are perpendicular to each other, then the angle between \(\hat{a}\) and \(\hat{b}\) is
71. If \(\vec{a}\), \(\vec{b}\) and \(\vec{c}\) are unit vectors such that \(\vec{a} \cdot \vec{b} = 0 = \vec{a} \cdot \vec{c}\) and the angle between \(\vec{b}\) and \(\vec{c}\) is \(\pi/3\), then the value of \(|\vec{a} \times \vec{b} - \vec{a} \times \vec{c}|\) is ________.
Example 30. Let A, B and C be unit vectors. Suppose A · B = A · C = 0 and the angle between B and C is π/4. Then:
We have \(\vec{b} \times \vec{c} = \vec{b} \times \vec{d}\). Then \(\vec{d}\) equals: