Let \(\vec{a},\, \vec{b},\, \vec{c}\) be three vectors of magnitude 2, 3, 5 respectively, satisfying \(|[\vec{a},\, \vec{b},\, \vec{c}]| = 30\). If \((2\vec{a} + \vec{b} + \vec{c}) \cdot ((\vec{a} \times \vec{c}) \times (\vec{a} - \vec{c}) + \vec{b}) = k\), then the value of \(\left(\dfrac{k}{103}\right)\) is:
Given \( \overrightarrow{OC} = m\overrightarrow{OA} + n\overrightarrow{OB} \), i.e., \( \vec{c} = m\vec{a} + n\vec{b} \), where \( |\vec{a}| = 1,\ |\vec{b}| = 1,\ |\vec{c}| = \sqrt{2},\ \tan\alpha = 7 \). Find the value of \( m + n \) (or the relevant expression as given in the problem).
In a triangle ABC, right-angled at the vertex A, if the position vectors of A, B and C are, respectively, \(3\hat{i}+\hat{j}-\hat{k}\), \(-\hat{i}+3\hat{j}+p\hat{k}\) and \(5\hat{i}+q\hat{j}-4\hat{k}\), then the point \((p, q)\) lies on a line
For \(p>0\), the vector \(\vec{v}_2=(2,\,-(\sqrt{3}\,p+1))\) is obtained by rotating \(\vec{v}_1=\sqrt{3}(-1,\,-(p^2+\sqrt{3}))\) about the origin counter-clockwise. If the angle of rotation is \(\theta\), find \(\tan\theta\).