If $\begin{vmatrix} \vec{a} - 2\vec{b} + \vec{c} & \vec{b} + 2\vec{c} + 3\vec{a} \\ \vec{a} & \vec{b} & \vec{c} \\ \vec{b} & \vec{b} & \vec{c} \\ \vec{c} & \vec{c} & \vec{c} \end{vmatrix} = 54$, where $\vec{a}$, $\vec{b}$, $\vec{c}$ are 3 non-coplanar vectors, then the value of $[\vec{a} \, \vec{b} \, \vec{c}]$ is equal to
Let the given points be A(−1, −1, 2), B(2, m, 5) and C(3, 11, 6). Find the value of m such that A, B and C are collinear.
If the vertices A, B, C of a △ABC have position vectors \((1, 2, 3)\), \((-1, 0, 0)\), \((0, 1, 2)\) respectively, then \(\angle ABC\) (the angle between the vectors \(\vec{BA}\) and \(\vec{BC}\)) is equal to
Given \(\vec{a} = 2\hat{i} + \lambda_1 \hat{j} + 3\hat{k}\), \(\vec{b} = 4\hat{i} + (3 - \lambda_2)\hat{j} + 6\hat{k}\) and \(\vec{c} = 3\hat{i} + 6\hat{j} + (\lambda_3 - 1)\hat{k}\), and \(\vec{b} = 2\vec{a}\), \(\vec{a}\) is perpendicular to \(\vec{c}\). Find the values of \((\lambda_1, \lambda_2, \lambda_3)\).