We have \(f(1) = -2\), \(f'(x) \geq 2\) for all \(x \in [1, 6]\). By LMVT, there exists \(c \in (1, 6)\) such that \(f'(c) = \frac{f(6) - f(1)}{5}\). Since \(f'(x) \geq 2\) for all \(x \in [1, 6]\), what is the minimum value of \(f(6)\)?
Let a curve $y=f(x),\ x\in(0,\infty)$ pass through the points $P\!\left(1,\dfrac{3}{2}\right)$ and $Q\!\left(a,\dfrac{1}{2}\right)$. If the tangent at any point $R(b,f(b))$ to the given curve cuts the $y$-axis at the point $S(0,c)$ such that $bc=3$, then $(PQ)^2$ is equal to _____.
The corner points of the feasible region determined by the system of linear constraints are \((0, 0)\), \((0, 40)\), \((20, 40)\), \((60, 20)\), \((60, 0)\). The objective function is \(z = 4x + 3y\).Compare the quantity in Column A and Column B:Column AColumn BMaximum of \(z\)325
Consider the triangles with vertices $A(2,1)$, $B(0,0)$ and $C(t,4)$, $t\in[0,4]$. If the maximum and the minimum perimeters of such triangles are obtained at $t=\alpha$ and $t=\beta$ respectively, then $6\alpha+21\beta$ is equal to ___________.