Definite Integration Questions (1340)

Evaluate: \[I = \int_{-\pi/2}^{\pi/2} \frac{2}{1+e^x}\, dx\]
For $n > 0$, $\int_{0}^{\pi} \frac{x\sin 2nx}{\sin^{2n} x + \cos^{2n} x} dx$ is
The value of definite integral \( \displaystyle\int_{-\pi}^{\pi} \dfrac{2x(1 + \sin x)}{1 + \cos^2 x}\, dx \) is:
Given \( I = \int_{\pi/6}^{\pi/3} \sec^{2/3} x \cdot \csc^{4/3} x \, dx \), find the value of \(I\).
Evaluate \(\displaystyle\int_0^{\pi/2}x\cos x\,dx\) [JEE Main 2018]
Let \(f(x) = \int_1^x \dfrac{\log t}{1+t}\,dt\). Then \(F(e) = f(e) + f\!\left(\dfrac{1}{e}\right)\) equals:
Let \(I = \int_{a}^{b} (x^4 - 2x^2) \, dx\). If \(I\) is minimum then the ordered pair \((a, b)\) is:
Evaluate: \(\displaystyle\int_0^{2\pi} \frac{x\sin^{2n} x}{\sin^{2n} x + \cos^{2n} x}\,dx\) (up to four decimal places).
$\displaystyle\lim_{n\to\infty}\left(\dfrac{1}{1+n}+\dfrac{1}{2+n}+\dfrac{1}{3+n}+\cdots+\dfrac{1}{2n}\right)$ is equal to:
If $a_1, a_2$ and $a_3$ are the three values of $a$ which satisfy the equation $\int_0^{\pi/2} (\sin x + a \cos x)^3 dx = \frac{4a}{\pi - 2} \int_0^{\pi/2} x \cos x dx = 2$ then $\left(a_1^2 + a_2^2 + a_3^2\right)$ is equal to ____.
\(\lim\limits _{n \rightarrow \infty} \frac{3}{n}\)\(\left\{4+\left(2+\frac{1}{n}\right)^2+\left(2+\frac{2}{n}\right)^2+. .+\left(3-\frac{1}{n}\right)^2\right\}\) is equal
Given \( g(x) = f(x+5) \), \( f(0) = 0 \), and \( g(x) \) is an even function. Find \( I = \int_0^x f(t)\,dt \) in terms of \(g\).
The integral \(\displaystyle\int_{\pi/2}^{\pi/4} \dfrac{8\cos 2x}{(\tan x + \cot x)^3}\,dx\) equals
If \(f(x)\) is a differentiable function defined for all positive real numbers such that \(xf(x) = x + \int_{1}^{x} f(t)\, dt\), then the value of \(\sum_{k=1}^{10} f(e^k)\) is:
Evaluate: \( I = \int_{\pi/4}^{3\pi/4} \dfrac{x}{1+\sin x} \, dx \)(1) \(\pi(\sqrt{2}+1)\)   (2) \(\pi(\sqrt{2}-1)\)   (3) \(\pi\sqrt{2}\)   (4) \(2\pi(\sqrt{2}-1)\)
If $\int_1^2 \frac{(x^2-1)dx}{x^3\sqrt{2x^4-2x^2+1}} = \frac{1}{k}$ then $k$ is____.
Let f and g be continuous functions on [-20, 20] such that f(-x) = f(x), g(-x) = -g(x), and g(x) = 1 + f(x)·f(-x). If \(\int_{-20}^{20} f(x)\,dx = 2020\), then \(I = \int_{-20}^{20} \dfrac{f(x)}{g(x)}\,dx\) equals:
Find \(\displaystyle\lim_{n \to \infty} \left[\frac{1}{n^2}\sec^2\!\left(\frac{1}{n^2}\right) + \frac{2}{n^2}\sec^2\!\left(\frac{4}{n^2}\right) + \cdots + \frac{1}{n^2}\sec^2 1\right]\).
The value of the integral \(\int_{-\pi/2}^{\pi/2} \sin^4 x \left(1 + \log\left(\dfrac{2+\sin x}{2-\sin x}\right)\right) dx\) is
Integrate: \(\int_{-1.5}^{3.5} |x-1|\, dx\).
If the value of the definite integral $\int_0^1 {^{207}}C_x x^{200}(1-x)^7 dx$ is equal to $1/k$ where $k \in \mathbb{N}$, then the value of $k/26$ is ____.
If \(f(x)+f(1-x)=1\) for all \(x\), find \(\displaystyle\int_0^1 f(x)\,dx\). [JEE Main 2016]
The value of \(\lim \limits_{n \rightarrow \infty} \frac{1}{n} \sum \limits_{r=0}^{2 n-1} \frac{n^2}{n^2+4 r^2}\) is:
If \([\;]\) denotes the greatest integer function, then the integral \(\displaystyle\int_0^{\pi}[\cos x]\,dx\) is equal to
Evaluate: \[\lim_{n \to \infty} \left[ \ln\left(\sqrt[n]{\frac{4}{n^2}}\right) + \ln\left(\sqrt[n]{\frac{16}{n^2}}\right) + \ln\left(\sqrt[n]{\frac{36}{n^2}}\right) + \cdots + \ln\left(\sqrt[n]{\frac{4n^2}{n^2}}\right) \right]\]
The value of definite integral \(\displaystyle\int_{\frac{-1}{\sqrt{3}}}^{\frac{1}{\sqrt{3}}} \frac{\cos^{-1}\!\left(\dfrac{2x}{1+x^2}\right) + \tan^{-1}\!\left(\dfrac{2x}{1-x^2}\right)}{e^x + 1}\,dx\) is equal to:
Question 586. The value of 'm' is equal to:
If \(\displaystyle\int_0^{\pi/3} \frac{\tan\theta}{\sqrt{2k\sec\theta}}\, d\theta = 1 - \dfrac{1}{\sqrt{2}}\), \((k > 0)\), then the value of \(k\) is:
Find $\int_{0}^{2} (x^2 + 1) dx$ as the limit of a sum.
Let f(x) = \(\int_0^x g(t)\,dt\), where g is a non-zero even function. If f(x + 5) = g(x), then \(\int_0^x f(t)\,dt\) equals:
If \(I = \int_0^1 (1-x^4)^7\, dx\), then the value of \(\dfrac{29\int_0^1(1-x^4)^7\,dx}{10\int_0^1(1-x^4)^6\,dx}\) is:
The value of $2^{2010} \frac{\int_0^1 x^{1004}(1-x)^{1004} dx}{\int_0^1 x^{1004}\left(1-x^{2010}\right)^{1004} dx}$ is ____.
Find a real number \(c\) and a positive number \(L\) for which \(\displaystyle\lim_{r \to \infty} \dfrac{r^c \int_0^{\pi/2} x^r \sin x\,dx}{\int_0^{\pi/2} x^r \cos x\,dx} = L\)
If \(I_1 = \int_{0}^{1} 2x^2 \, dx\), \(I_2 = \int_{0}^{1} 2x^3 \, dx\), \(I_3 = \int_{1}^{2} 2x^2 \, dx\) and \(I_4 = \int_{1}^{2} 2x^3 \, dx\), then
Evaluate \(\displaystyle\int_0^{\pi/2}\frac{\sin x-\cos x}{1+\sin x\cos x}\,dx\) [JEE Main 2016]
If the system of equations 2x - y + z = 0, x + 2y + z = 0, tx - y + 2z = 0 has infinitely many solutions and f(x) be a continuous function such that f(5 - x) + f(x) = 2, then \int_{0}^{2t} f(x)\,dx is equal to
If \(m\) and \(n\) are positive integers and \(\int_a^b (t - a)^{2n} ((t - b)^{2m+1} \, dt\), \(a
$\displaystyle\lim_{x\to0}\dfrac{48}{x^4}\int_0^x\dfrac{t^3}{t^6+1}\,dt$ is equal to ___.
Given \( I = \int_a^b (x^4 - 2x^2)\,dx \) and \( f(x) = x^2(x^2 - 2) \). Find the ordered pair \((a, b)\) such that \(I\) is minimum.
If \(f(2-x) = f(2+x)\) and \(f(4-x) = f(4+x)\) and \(f(x)\) is a function for which \(\int_0^2 f(x)\,dx = 5\), then \(\int_0^{50} f(x)\,dx\) is equal to
The value of \(\int_{-2}^{3} |1-x^2|\, dx\) is:
We have \[I = \int_0^\pi x f(\sin x)\,dx\] Using the property of definite integrals, find the value of \(I\).
Evaluate \(\int_0^{\pi/2} \dfrac{\sqrt{\sin x}}{\sqrt{\sin x} + \sqrt{\cos x}}\, dx\)
Let function \(F\) be defined as \(F(x) = \displaystyle\int_1^x \dfrac{e^t}{t}\,dt,\; x > 0\), then the value of the integral \(\displaystyle\int_1^x \dfrac{e^t}{t+a}\,dt\), where \(a > 0\), is
If \( I_n = \displaystyle\int_0^{\pi/2} \dfrac{\sin^2 nx}{\sin x} \, dx \), then \( I_{n+1} + I_{n-1} - 2I_n \) equals:
\(\int_0^{\pi} [\cot x]\, dx\), where \([\cdot]\) denotes the greatest integer function, is equal to
Evaluate\(\int_2^3 2 x^2 e^{x^3} d x\).  
The integral \(\displaystyle\int_0^{1/2}\dfrac{\ln(1+2x)}{1+4x^2}\,dx\) equals:
The value of \(\int_0^{\pi} \sqrt{1 + 4\sin^2\dfrac{x}{2} - 4\sin\dfrac{x}{2}}\,dx\) is:
Evaluate \(\int_0^1 \dfrac{\ln(x+1)}{x^2+1}\,dx\)