Determinants Questions (2072)

The number of \(3 \times 3\) non-singular matrices, with four entries as 1 and all other entries as 0, is
If \(f(x) = a + bx + cx^2\) and \(\alpha, \beta, \gamma\) are the roots of the equation \(x^2 = 1\), then \(\begin{vmatrix} a & b & c \\ b & c & a \\ c & a & b \end{vmatrix}\) is equal to
Let \(\vec{a}_r = x_r\hat{i} + y_r\hat{j} + z_r\hat{k}\), \(r = 1, 2, 3\) be three mutually perpendicular unit vectors, then the value of \(\begin{vmatrix} x_1 & x_2 & x_3 \\ y_1 & y_2 & y_3 \\ z_1 & z_2 & z_3 \end{vmatrix}\) is equal to
If \(A_r = \begin{vmatrix} 2^{r-1} & 2 \times 3^{r-1} & 4 \times 5^{r-1} \\ \alpha & \beta & \gamma \\ 2^n - 1 & 3^n - 1 & 5^n - 1 \end{vmatrix}\), then find the value of \(\displaystyle\sum_{r=1}^{n} A_r\).
The value of the determinant \[\begin{vmatrix} (a_1-b_1)^2 & (a_1-b_2)^2 & (a_1-b_3)^2 & (a_1-b_4)^2 \\ (a_2-b_1)^2 & (a_2-b_2)^2 & (a_2-b_3)^2 & (a_2-b_4)^2 \\ (a_3-b_1)^2 & (a_3-b_2)^2 & (a_3-b_3)^2 & (a_3-b_4)^2 \\ (a_4-b_1)^2 & (a_4-b_2)^2 & (a_4-b_3)^2 & (a_4-b_4)^2 \end{vmatrix}\] is
If \(a - b + c = 0\), then one root of \(\begin{vmatrix} a-x & c & b \\ c & b-x & a \\ b & a & c-x \end{vmatrix} = 0\) is
For Problems 16–18Consider the polynomial function\[f(x) = \begin{vmatrix} (1+x)^a & (1+2x)^b & 1 \\ 1 & (1+x)^a & (1+2x)^b \\ (1+2x)^b & 1 & (1+x)^a \end{vmatrix}\]\(a, b\) being positive integers.The constant term in \(f(x)\) is
For Problems 22–24Consider the system of equations\(x + y + z = 6\)\(x + 2y + 3z = 10\)\(x + 2y + \lambda z = \mu\)The system has infinite solutions if
If \(\begin{vmatrix} x^n & x^{n+2} & x^{2n} \\ 1 & x^a & a \\ x^{n+5} & x^{a+6} & x^{2n+5} \end{vmatrix} = 0, \forall x \in R\), where \(n \in N\), then value of \(a\) is
Prove that \[\begin{vmatrix} 1+a & 1 & 1 & 1 \\ 1 & 1+b & 1 & 1 \\ 1 & 1 & 1+c & 1 \\ 1 & 1 & 1 & 1+d \end{vmatrix} = abcd\left(1 + \frac{1}{a} + \frac{1}{b} + \frac{1}{c} + \frac{1}{d}\right).\] Hence, find the value of the determinant if \(a, b, c, d\) are the roots of the equation \(px^4 + qx^3 + rx^2 + sx + t = 0\).
The total number of distinct \(x \in R\) for which \[\begin{vmatrix} x & x^2 & 1+x^3 \\ 2x & 4x^2 & 1+8x^3 \\ 3x & 9x^2 & 1+27x^3 \end{vmatrix} = 10\] is ___. (JEE Advanced 2016)
Which must be true: I) $A,B$ square matrices of same order, $O$ null, $I$ identity. If $AB=O$, then $(\det A)^2+(\det B)^2=0$. II) If $l_i,m_i,n_i$ $(i=1,2,3)$ are direction cosines of 3 mutual perpendicular vectors, then $A=\begin{pmatrix}l_1&m_1&n_1\\l_2&m_2&n_2\\l_3&m_3&n_3\end{pmatrix}$ is orthogonal. III) For two distinct lines with shortest distance $d\ne 0$, a point $A$ on line 1 and $B$ on line 2 with $AB=d$: $A$ and $B$ are unique.
If \(A^2 - A + I = 0\), then the inverse of A is
A is a \(2 \times 2\) matrix such that \(A\begin{bmatrix}1\\-1\end{bmatrix} = \begin{bmatrix}-1\\2\end{bmatrix}\) and \(A^2\begin{bmatrix}1\\-1\end{bmatrix} = \begin{bmatrix}1\\0\end{bmatrix}\). The sum of the elements of A is
If \(k \in R_0\), then \(\det(\text{adj}(kI_n))\) is equal to
If a, b and c are non-zero real numbers and if the equations (a-1)x = y + z, (b-1)y = z + x, (c-1)z = x + y has a non-trivial solution, then ab + bc + ca equals
Let k be a positive real number and \[A = \begin{bmatrix} 2k-1 & 2\sqrt{k} & 2\sqrt{k} \\ 2\sqrt{k} & 1 & -2k \\ -2\sqrt{k} & 2k & -1 \end{bmatrix}\] and \[B = \begin{bmatrix} 0 & 2k-1 & \sqrt{k} \\ 1-2k & 0 & 2 \\ -\sqrt{k} & -2\sqrt{k} & 0 \end{bmatrix}.\] If \(\det(\text{adj}\, A) + \det(\text{adj}\, B) = 10^6\), then \([k]\) is equal to ___. [Note: adj M denotes the adjoint of a square matrix M and \([k]\) denotes the largest integer less than or equal to \(k\).]
The number of solutions of the matrix equation \(X^2 = \begin{bmatrix} 1 & 1 \\ 2 & 3 \end{bmatrix}\) is
The number of distinct real roots of the equation \(\begin{vmatrix} \cos x & \sin x & \sin x \\ \sin x & \cos x & \sin x \\ \sin x & \sin x & \cos x \end{vmatrix} = 0\) in the interval \(\left[-\dfrac{\pi}{4}, \dfrac{\pi}{4}\right]\) is
There are two possible values of A in the solution of the matrix equation \(\begin{bmatrix} 2A+1 & -5 \\ -4 & A \end{bmatrix}^{-1} \begin{bmatrix} A-5 & B \\ 2A-2 & C \end{bmatrix} = \begin{bmatrix} 14 & D \\ E & F \end{bmatrix}\), where A, B, C, D, E and F are real numbers. The absolute value of the difference of the two solutions is
If \(A = \begin{bmatrix} 0 & 1 & 2 \\ 1 & 2 & 3 \\ 3 & a & 1 \end{bmatrix}\) and \(A^{-1} = \begin{bmatrix} 1/2 & 1/2 & 1/2 \\ -4 & 3 & c \\ 5/2 & -3/2 & 1/2 \end{bmatrix}\), then the values of a and c are equal to
If \(\begin{vmatrix} 6i & -3i & 1 \\ 4 & 3i & -1 \\ 20 & 3 & i \end{vmatrix} = x + iy\), then