Let \(H: \frac{-x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\) be the hyperbola, whose eccentricity is \(\sqrt{3}\) and the length of the latus rectum is \(4 \sqrt{3}\). Suppose the point (\(\alpha, 6\)), \(\alpha \gt 0\) lies on \(H\). If \(\beta\) is the product of the focal distances of the point (\(\alpha, 6\)), then \(\alpha^{2}+\beta\) is equal to: