How many six-digit odd numbers, greater than 6,00,000, can be formed from the digits 5, 6, 7, 8, 9, and 0 if(a) repetition of digits is allowed?
The number of integers greater than 6,000 that can be formed, using the digits 3, 5, 6, 7 and 8, without repetition, is
The total number of functions, f:{1, 2, 3, 4} \(\rightarrow\) {1, 2, 3, 4, 5, 6} such that f(1) + f(2) = f(3), is equal to:
Four-digit numbers are formed using digits from $\{0,1,2,3,4,5\}$, repetition allowed. Statement $S_1$: the number of such odd numbers is 480. Statement $S_2$: the number formed with exactly three different digits is 360.
If \(a, b, c, d\) are odd natural numbers such that \(a + b + c + d = 20\), then find the number of values of the ordered quadruplet \((a, b, c, d)\).
Words of length 10 are formed using the letters \(A, B, C, D, E, F, G, H, I, J\). Let \(x\) be the number of such words where no letter is repeated; and let \(y\) be the number of such words where exactly one letter is repeated twice and no other letter is repeated. Then \(\dfrac{y}{9x}\) = ________.
Let \(A = \{x_1, x_2, x_3, \ldots, x_7\}\), \(B = \{y_1, y_2, y_3\}\). The total number of functions \(f: A \to B\) that are on to and there are exactly three elements \(x\) in \(A\) such that \(f(x) = y_2\) is equal to