Straight Lines Questions (433)

Given line is \(5x - y = 1\). A line \(L\) is perpendicular to it. The area of the triangle formed by line \(L\), line \(5x - y = 1\), and the origin is 5 square units. The distance of line \(L\) from origin is:
A ray of light is incident on a mirror. The normal at the point of incidence makes an angle of 30° with the horizontal. If the point of incidence is \((\sqrt{3}, 0)\) and a point (0, 1) lies on the ray of light (on the line), then the equation of the reflected ray is:
Three lines have slopes \(m_1 = 5\), \(m_2 = 3\), \(m_3 = -1\) (arranged in descending order). The angles \(A\), \(B\), \(C\) between consecutive lines satisfy:\(\tan A = \dfrac{m_1 - m_2}{1 + m_1 m_2} = \dfrac{2}{1+15} = \dfrac{1}{8}\)\(\tan B = \dfrac{m_2 - m_3}{1 + m_2 m_3} = \dfrac{3+1}{1-3} = -2\)\(\tan C = \dfrac{m_3 - m_1}{1 + m_3 m_1} = \dfrac{-1-5}{1-5} = \dfrac{3}{2}\)If \(\displaystyle\sum \tan^2 A = \dfrac{1}{64} + 4 + \dfrac{9}{4} = \dfrac{p+q}{93}\), find \(\dfrac{p+q}{93}\).
If a variable line drawn through the intersection of the lines \(\dfrac{x}{3} + \dfrac{y}{4} = 1\) and \(\dfrac{x}{4} + \dfrac{y}{3} = 1\) meets the coordinate axes at A and B, (A ≠ B), then the locus of the mid-point of AB is
The given lines \(L_1\) and \(L_2\) are parallel and the distance between them (\(BC\) or \(AD\)) is \((15-5)/5 = 2\) units. A parallelogram \(AA_1BB_1\) is formed. The area of the parallelogram is least for \(\theta = \pi/4\). If the slope of \(AB\) is \(m\), then \(1 = \left|\dfrac{m + 3/4}{1 - \dfrac{3m}{4}}\right|\). Find the slope \(m\) and hence the equation of line \(L\). The minimum area of the parallelogram \(AA_1BB_1\) is:
Number of possible ordered pair(s) \((x, y)\) of all positions of point P on AB so that area of the rectangle PDOC is 30 sq. units is:
A triangle with vertices (4, 0), (−1, −1), (3, 5) is
Let k be an integer such that the triangle with vertices (k, −3k), (5, k) and (−k, 2) has area 28 sq. units. Then the orthocentre of this triangle is at the point:
A vertex of an equilateral triangle is \((2, 3)\) and the equation of the opposite side is \(x + y = 2\). Find the equations of the other two sides and the length of each side of the triangle.
Let ABCD be a parallelogram, the equations of whose diagonals are \(AC: x + 2y - 3 = 0\) and \(BD: 2x + y - 3 = 0\). If the length of the diagonal \(AC = 4\) units and the area of the parallelogram \([ABCD] = 8\) square units. The length of side BD is:
The x-coordinate of the incentre of the triangle that has the coordinates of midpoints of its sided as \((0, 1)\), \((1, 1)\) and \((1, 0)\) is
The points (2, 5) and (5, 1) are two opposite vertices of a rectangle. If other two vertices are points on the straight line \(y = 2x + k\), then the value of \(k\) is:
Let \(A(2, -3)\) and \(B(-2, 1)\) be vertices of a triangle \(ABC\). If the centroid of this triangle moves on the line \(2x + 3y = 1\), then the locus of the vertex C is the line
A straight line through a fixed point \((2, 3)\) intersects the coordinate axes at distinct points \(P\) and \(Q\). If \(O\) is the origin and the rectangle \(OPRQ\) is completed, then the locus of \(R\) is
The equation of the pair of bisectors of the angles between the pair of lines represented by \(ax^2 + 2hxy + ay^2 = 0\) if the product of slopes of four lines represented by a given equation is 1 and a pair of lines represents the bisectors of angles between the other two, then the product of the slopes of each pair is:
Let \(a\), \(b\), \(c\) and \(d\) be non-zero numbers. If the point of intersection of the lines \(4ax + 2ay + c = 0\) and \(5bx + 2by + d = 0\) lies in the fourth quadrant and is equidistant from the two axes then
Two lines \(y = -\sqrt{3}x\) and \(y = \sqrt{3}x\) intersect at the origin. A point \(P(2, 2)\) is given. If \(B\) is a point on the line \(y = \sqrt{3}x\) and \(K\) is on line \(y = \sqrt{3}x\) such that \(\angle AOB = 60°\) (where \(O\) is origin and \(\triangle OAB\) is equilateral), then \(\angle KBP\) equals:
In triangle ABC with H as orthocenter at origin (0, 0), B = (-2, 3), and C = (5, -1), find the coordinates of vertex A.
Question 86: Statement-1: If the system of equations $2x + 3y = a$ and $bx + 4y = 5$ has infinite solutions, then $a = \frac{15}{8}$, $b = \frac{8}{5}$.Statement-2: Straight lines $a_1 x + b_1 y + c_1 = 0$ and $a_2 x + b_2 y + c_2 = 0$ are parallel if $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$.
Suppose that the points (h, k), (1, 2) and (-3, 4) lie on the line L_1. If a line L_2 passing through the points (h, k) and (4, 3) is perpendicular to L_1, then k/h equals
Without changing the direction of coordinate axes, the origin is shifted to (h, k), then from the equation x^2 + y^2 - 4x + 6y - 7 = 0 the terms containing linear powers are missing. Then, point (h, k) is
The distance between the lines \(5x - 12y + 65 = 0\) and \(10x - 24y - 39 = 0\) is
ABC is an isosceles triangle. If the coordinates of the base are B(1, 3) and C(-2, 7), the coordinates of vertex A is
If the points $(0, 0)$, $(2, 2\sqrt{3})$ and $(a, b)$ are the vertices of an equilateral triangle, then $(a, b)$ is
Let L denote the line in the xy-plane with x and y intercepts as 3 and 1 respectively. Then, the image of the point (−1, −4) in this line is
The area of the pentagon whose vertices are A(1, 1), B(7, 21), C(7, -3), D(12, 2) and E(0, -3), is
If $L = \left(\frac{1}{x_l}\right), M = \left(\frac{1}{x_m}\right), N = \left(\frac{1}{x_n}\right)$ where $x_k \neq 0$, denotes the $k^{th}$ terms of a H.P. for $k \in N$, then:
The orthocentre of the triangle with vertices \((5, 0)\), \((0, 0)\), \(\left(\frac{5}{2}, \frac{5\sqrt{3}}{2}\right)\) is:
The locus of centroid of the triangle whose vertices are (a cos t, a sin t) (b sin t, - b cos t) and (1, 0) where t is a parameter, is :
Find the value of the y-intercept \(c\) of the line \(y = 2x + c\) such that the perpendicular distance from the origin to this line equals 5.
The value of $a+b+c$ equals:
Let the equations of two sides of a triangle be \(3x - 2y + 6 = 0\) and \(4x + 5y - 20 = 0\). If the orthocentre of this triangle is at (1, 1), then the equation of its third side is:
Which of the following can't be the vertex of the triangle:
Which of the following can be possible orthocenter of the triangle:
For what values of λ the following three lines are concurrent?\(x + y = 1\), \(\lambda x + 2y = 3\), \(\lambda^2 x + 4y + 9 = 0\)
In a $\triangle ABC$, the vertex $A$ is $(1, 1)$ and orthocenter is $(2, 4)$. If the sides $AB$ and $BC$ are members of the family of straight lines $ax + by + c = 0$. Where $a, b, c$ are in A.P., then the coordinates of vertex $C$ are $(h, k)$. The value of $2h + 9k$ is ________.
Two equal sides $OA$ and $OB$ of an isosceles triangle lie in the first quadrant. If the slopes of $OA$ and $OB$ are $\frac{7}{17}$ and $1$, respectively and the length of perpendicular from $O$ to $AB$ is $\sqrt{13}$, if the equation of the side $AB$ is $ax + by = c$ then the value of $(c - a - b)$ is __________.
A line intersects the x-axis at $A(7, 0)$ and y-axis $B(0, -5)$. A variable line $PQ$ perpendicular to $AB$ intersects the x-axis at $P$ and the y-axis at $Q$. If $AQ$ and $BP$ intersect at $R$, show that the locus of $R$ is $x^2 + y^2 - ax + by = 0$. Then the value of $(a - b)$ is ______.
In a triangle $ABC$, the coordinates of $A$ is $(1, 2)$ and the equations to the medians through $B$ and $C$ are $x + y = 5$ and $x = 4$. If coordinate of $B$ is $(x_1, y_1)$ and co-ordinate of $C$ is $(x_2, y_2)$ then $x_1y_2 + x_2y_1$ equals____.
If the equal sides $PQ$ and $PR$ (each equal to 2) of a right angled isosceles $\triangle PQR$ be produced to $A$ and $B$ so that $OA.RB = PR^2$ then the line $AB$ passes through a fixed point which also satisfies the line $ax + by - 6 = 0$ then $a + b$ is ____.
If from point $P$ (4, 4) perpendiculars to the straight lines $3x + 4y + 5 = 0$ and $y = mx + 7$ meet at $Q$ and $R$ respectively and area of triangle $PQR$ is maximum. Then the value of $12m$ must be ____.
The number of possible straight lines, passing through (2, 3) and forming a triangle with coordinate axes, whose area is 12 sq. units, is:
Let a line passing through point A divides the square ABCD into two parts so that area of one portion is double the other, then the length of portion of line inside the square is:
The line (k + 1)2x + ky - 2k^2 - 2 = 0 passes through a point regardless of the value k. Which of the following is the line with slope 2 passing through the point ?
If $6a^2 - 3b^2 - c^2 + 7ab - ac + 4bc = 0$, then the family of lines $ax + by + c = 0$ is concurrent at ordered pairs $(A, B)$ and $(C, D)$. $A > 0$ then the value of $A - B - C - D$ is ______.
If an equilateral triangle has one vertex at the point (0, 0) and another at (3, \sqrt{3}), then the coordinates of the third vertex is
Given A (0, 0) and B (x, y) with x ∈ (0, 1) and y > 0. Let the slope of the line AB equals m₁. Point C lies on the line x = 1 such that the slope of BC equals m₂ where 0
Two opposite vertices of a rectangle are (1, 3) and (5, 1). If the rest two vertices lie on the line y - x + l = 0, then l is equal to
The ordered pair (x, y) is, where H(x, y) are the coordinates of the orthocentre of triangle ABC with vertices A(9, 3), B(7, –1) and C(1, –1).
A straight line L through the point (3, −2) is inclined at an angle of 60° to the line \(\sqrt{3}x + y = 1\). If L also intersects the x-axis, then the equation of L is