Three lines have slopes \(m_1 = 5\), \(m_2 = 3\), \(m_3 = -1\) (arranged in descending order). The angles \(A\), \(B\), \(C\) between consecutive lines satisfy:\(\tan A = \dfrac{m_1 - m_2}{1 + m_1 m_2} = \dfrac{2}{1+15} = \dfrac{1}{8}\)\(\tan B = \dfrac{m_2 - m_3}{1 + m_2 m_3} = \dfrac{3+1}{1-3} = -2\)\(\tan C = \dfrac{m_3 - m_1}{1 + m_3 m_1} = \dfrac{-1-5}{1-5} = \dfrac{3}{2}\)If \(\displaystyle\sum \tan^2 A = \dfrac{1}{64} + 4 + \dfrac{9}{4} = \dfrac{p+q}{93}\), find \(\dfrac{p+q}{93}\).
Suppose that the points (h, k), (1, 2) and (-3, 4) lie on the line L_1. If a line L_2 passing through the points (h, k) and (4, 3) is perpendicular to L_1, then k/h equals
The area of the pentagon whose vertices are A(1, 1), B(7, 21), C(7, -3), D(12, 2) and E(0, -3), is
In a $\triangle ABC$, the vertex $A$ is $(1, 1)$ and orthocenter is $(2, 4)$. If the sides $AB$ and $BC$ are members of the family of straight lines $ax + by + c = 0$. Where $a, b, c$ are in A.P., then the coordinates of vertex $C$ are $(h, k)$. The value of $2h + 9k$ is ________.
The ordered pair (x, y) is, where H(x, y) are the coordinates of the orthocentre of triangle ABC with vertices A(9, 3), B(7, –1) and C(1, –1).