In a triangle ABC, right-angled at the vertex A, if the position vectors of A, B and C are, respectively, \(3\hat{i}+\hat{j}-\hat{k}\), \(-\hat{i}+3\hat{j}+p\hat{k}\) and \(5\hat{i}+q\hat{j}-4\hat{k}\), then the point \((p, q)\) lies on a line
For \(p>0\), the vector \(\vec{v}_2=(2,\,-(\sqrt{3}\,p+1))\) is obtained by rotating \(\vec{v}_1=\sqrt{3}(-1,\,-(p^2+\sqrt{3}))\) about the origin counter-clockwise. If the angle of rotation is \(\theta\), find \(\tan\theta\).
Let \(\vec{a}=2\hat{i}+3\hat{j}-\hat{k}\), \(\vec{b}=\hat{i}-\hat{j}+2\hat{k}\), \(\vec{c}=2\hat{i}+\hat{j}-\hat{k}\). If \([\vec{a}+\vec{b},\,\vec{b}+\vec{c},\,\vec{c}+\vec{a}]=\lambda[\vec{a},\vec{b},\vec{c}]\), find \(\lambda\).
We have a, b, c are non-zero vectors and \(\vec{a} \neq \lambda_1 \vec{b}\) and \(\vec{b} \neq \mu_1 \vec{c}\), \(\lambda_1, \mu_1 \neq 0\). Given:\(\vec{a} + 2\vec{b} = m\vec{c}\) ...(1)and \(\vec{b} + 3\vec{c} = n\vec{a}\) ...(2)where \(m, n \neq 0\) are reals. Find \(\vec{a} + 2\vec{b} + 6\vec{c}\) = ?