If the vertices A, B, C of a △ABC have position vectors \((1, 2, 3)\), \((-1, 0, 0)\), \((0, 1, 2)\) respectively, then \(\angle ABC\) (the angle between the vectors \(\vec{BA}\) and \(\vec{BC}\)) is equal to
Given \(\vec{a} = 2\hat{i} + \lambda_1 \hat{j} + 3\hat{k}\), \(\vec{b} = 4\hat{i} + (3 - \lambda_2)\hat{j} + 6\hat{k}\) and \(\vec{c} = 3\hat{i} + 6\hat{j} + (\lambda_3 - 1)\hat{k}\), and \(\vec{b} = 2\vec{a}\), \(\vec{a}\) is perpendicular to \(\vec{c}\). Find the values of \((\lambda_1, \lambda_2, \lambda_3)\).
Let \(\vec{a},\, \vec{b},\, \vec{c}\) be three vectors of magnitude 2, 3, 5 respectively, satisfying \(|[\vec{a},\, \vec{b},\, \vec{c}]| = 30\). If \((2\vec{a} + \vec{b} + \vec{c}) \cdot ((\vec{a} \times \vec{c}) \times (\vec{a} - \vec{c}) + \vec{b}) = k\), then the value of \(\left(\dfrac{k}{103}\right)\) is:
Given \( \overrightarrow{OC} = m\overrightarrow{OA} + n\overrightarrow{OB} \), i.e., \( \vec{c} = m\vec{a} + n\vec{b} \), where \( |\vec{a}| = 1,\ |\vec{b}| = 1,\ |\vec{c}| = \sqrt{2},\ \tan\alpha = 7 \). Find the value of \( m + n \) (or the relevant expression as given in the problem).