Let the position vectors of \(A\), \(B\), \(C\) and \(D\) be \(\vec{a}\), \(\vec{b}\), \(\vec{c}\) and \(\vec{d}\) respectively. Given that \(OA : CB = 2 : 1\) and \(OD : AB = 1 : 3\), and \(OX : XC = \lambda : 1\), \(AX : XD = \mu : 1\). Find \(OX : XC\).
The volume of the parallelepiped whose coterminous edges are represented by the vectors $2\mathbf{b} \times \mathbf{c}$, $3\mathbf{c} \times \mathbf{a}$ and $4\mathbf{a} \times \mathbf{b}$ where $\mathbf{a} = (1 + \sin \theta)\mathbf{i} + \cos \theta \mathbf{j} + \sin 2\theta \mathbf{k}$, $\mathbf{b} = \sin\left(\theta + \frac{2\pi}{3}\right)\mathbf{i} + \cos\left(\theta + \frac{2\pi}{3}\right)\mathbf{j} + \sin\left(2\theta + \frac{4\pi}{3}\right)\mathbf{k}$, $\mathbf{c} = \sin\left(\theta - \frac{2\pi}{3}\right)\mathbf{i} + \cos\left(\theta - \frac{2\pi}{3}\right)\mathbf{j} + \sin\left(2\theta - \frac{4\pi}{3}\right)\mathbf{k}$ is 18 cubic units, then the value of $\theta$ in the interval $\left(0, \frac{\pi}{2}\right)$ is:
Ex. 22 If a, b, c be non-zero vectors such that a is perpendicular to b and c and \(|\mathbf{a}| = 1\), \(|\mathbf{b}| = 2\), \(|\mathbf{c}| = 1\), \(\mathbf{b} \cdot \mathbf{c} = 1\) and there is a non-zero vector d coplanar with \(\mathbf{a} + \mathbf{b}\) and \(2\mathbf{b} - \mathbf{c}\) and \(\mathbf{d} \cdot \mathbf{a} = 1\), then minimum value of \(|\mathbf{d}|\) is
If three points A, B and C have position vectors \((1, x, 3)\), \((3, 4, 7)\) and \((y, -2, -5)\) respectively and if they are collinear, then \((x, y)\) is equal to
Let position vectors of $A,B,C,D$ be $5\hat{i}+5\hat{j}+2\lambda\hat{k}$, $\hat{i}+2\hat{j}+3\hat{k}$, $-2\hat{i}+\lambda\hat{j}+4\hat{k}$ and $-\hat{i}+5\hat{j}+6\hat{k}$. Let $S=\{\lambda\in\mathbb{R}: A,B,C,D\text{ coplanar}\}$. Then $\sum_{\lambda\in S}(\lambda+2)^2$ is equal to
Let $\vec{a}=2\hat{i}+\alpha\hat{j}+\hat{k}$, $\vec{b}=-\hat{i}+\hat{k}$, $\vec{c}=\beta\hat{j}-\hat{k}$, where $\alpha$ and $\beta$ are integers and $\alpha\beta=-6$. Let the values of the ordered pair $(\alpha,\beta)$, for which the area of the parallelogram of diagonals $\vec{a}+\vec{b}$ and $\vec{b}+\vec{c}$ is $\dfrac{\sqrt{21}}{2}$, be $(\alpha_1,\beta_1)$ and $(\alpha_2,\beta_2)$. Then $\alpha_1^2+\beta_1^2-\alpha_2\beta_2$ is equal to