Let A, B, C be three points in xy-plane, whose position vector are given by \sqrt3^i + ^j, ^i + \sqrt3^j and a^i + (1 - a)^j respectively with respect to the origin O . If the distance of the point C from the line bisecting the angle between - -\to - -\to the vectors OA and OB is , then the sum of all the possible values of a is : 9 \sqrt2
If the position vectors of the vertices A, B and C of a \(\triangle ABC\) are, respectively, \(4\hat{i}+7\hat{j}+8\hat{k}\), \(2\hat{i}+3\hat{j}+4\hat{k}\) and \(2\hat{i}+5\hat{j}+7\hat{k}\), then the position vector of the point, where the bisector of \(\angle A\) meets BC is
Let \(\vec{a}, \vec{b}, \vec{c}\) be three vectors of magnitude 2, 3, 5 respectively, satisfying \(|[\vec{a},\, \vec{b},\, \vec{c}]| = 30\). If \((2\vec{a} + \vec{b} + \vec{c}) \cdot ((\vec{a} \times \vec{c}) \times (\vec{a} - \vec{c}) + \vec{b}) = k\), then the value of \(\left\lfloor \dfrac{k}{103} \right\rfloor\) is:
Let A, B, C be three points in the $xy$-plane, whose position vectors are given by $\sqrt{3}\hat{i}+\hat{j}$, $\hat{i}+\sqrt{3}\hat{j}$ and $a\hat{i}+(1-a)\hat{j}$ respectively with respect to the origin $O$. If the distance of the point $C$ from the line bisecting the angle between the vectors $\overrightarrow{OA}$ and $\overrightarrow{OB}$ is $\dfrac{9}{\sqrt{2}}$, then the sum of all the possible values of $a$ is:
Consider a $\triangle ABC$ where $A(1,2,3)$, $B(-2,8,0)$ and $C(3,6,7)$. If the angle bisector of $\angle BAC$ meets the line $BC$ at $D$, then the length of the projection of the vector $\overrightarrow{AD}$ on the vector $\overrightarrow{AC}$ is: