Given: \(4x^2 - 9y^2 = 36\). The equation of hyperbola is \(\frac{x^2}{9} - \frac{y^2}{4} = 1\). A point \(Q(3\sec\theta, 2\tan\theta)\) is on the hyperbola. The normal at \(Q\) meets the co-ordinate axes at \(A\left(\frac{13}{3}\sec\theta, 0\right)\) and \(B\left(0, \frac{13}{2}\tan\theta\right)\). If \(OABP\) is a parallelogram and coordinate of \(P\) is \((h, k)\), then the locus of \(P\) is: