Inverse Trigonometry Questions (1043)

If $\cos \alpha + \cos \beta = a$, $\sin \alpha + \sin \beta = b$ and $\alpha - \beta = 2\theta$, then $\tan \frac{\alpha}{\tan \frac{\alpha}{2}} = \frac{a^2 + b^2 - 3}{\text{}}$
If $P$ be any interior point of the equilateral $\triangle ABC$ of side length $2$ units and also $x_a, x_b, x_c$ be the distances of $P$ from the sides $BC, CA, AB$ respectively, then $x_a + x_b + x_c =$
The value of $\cot^{-1}\left(2^2-\frac{1}{2}\right)+\cot^{-1}\left(2^3+\frac{1}{2^2}\right)+\cot^{-1}\left(2^4+\frac{1}{2^3}\right)+\ldots \infty$ is:
If \(\cos^{-1}(2x^2-1)=2\pi-2\cos^{-1}x\), then:
A chimney of 20 m height standing on the top of a building subtends an angle whose tangent is $\frac{1}{4}$ at a distance of 70 m from the foot of the building, then the height of building is
The domain of \(f(x)=\sin^{-1}(\log_2(x/3))\) is:
All \(x\) satisfying \((\sin^{-1}x)^2-(\cos^{-1}x)^2>0\):
If \(\alpha,\beta\) are roots of \(x^2-3x+2=0\), then \(\tan^{-1}\alpha+\tan^{-1}\beta=\)
\(\tan^{-1}\!\left(1-x^2-\dfrac{1}{x^2}\right)+\sin^{-1}\!\left(x^2+\dfrac{1}{x^2}-1\right)\), \(x\ne 0\), equals:
If $\displaystyle\sum_{n=1}^{\infty} \cot^{-1}\!\left(2 + \frac{n(n+1)}{2}\right) = \tan^{-1} a$, then $a$ is equal to
A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45°. It flies off horizontally straight away from O. After 1 second, the elevation of the bird from O is reduced to 30°. The speed (in m/s) of the bird is
If \(p = \cos 55°\), \(q = \cos 65°\) and \(r = \cos 175°\), then the value of \(\dfrac{1}{p} + \dfrac{1}{q} + \dfrac{r}{pq}\) is equal to:
If \(\cos^{-1}\!\left(\dfrac{2}{3x}\right) + \cos^{-1}\!\left(\dfrac{3}{4x}\right) = \dfrac{\pi}{2}\) \(\left(x > \dfrac{3}{4}\right)\), then \(x\) is equal to:
If \(\tan^{-1}x+\tan^{-1}y+\tan^{-1}z=\pi/2\), then \(xy+yz+zx=\)
\(\cot\!\left(\sum_{n=1}^{19}\cot^{-1}\!\left(1+\sum_{p=1}^{n}2p\right)\right)=\)
The value of $\displaystyle\sum_{r=2}^{\infty} \cot^{-1}(r^2 - 5r + 7)$ is
Find the value of \(\cos\left(\cos^{-1}\frac{\pi}{3} + \sin^{-1}\sin\frac{2\pi}{3}\right)\).
If $a=2$, then the sum of the infinite series $\cot^{-1}(2a^{-1}+a)+\cot^{-1}(2a^{-1}+3a)+\cot^{-1}(2a^{-1}+6a)+\cot^{-1}(2a^{-1}+10a)+\cdots$ is
If $\displaystyle\sum_{n=1}^{\infty} \cot^{-1}\!\left(2 + \frac{n(n+1)}{2}\right) = \tan^{-1} a$, then $a$ is equal to
If \(\sum_{i=1}^{10}\sin^{-1}x_i=5\pi\), then \(\sum_{i=1}^{10}x_i^2=\)
The value of the angle \(\tan^{-1}(\tan 65° - 2\tan 40°)\) in degrees is equal to
If \(\cos^{-1}\frac{x}{a} - \sin^{-1}\frac{y}{b} = 0\) (where \(a, b > 0\)), then the maximum value of \(b^2x^2 + a^2y^2 + 2abxy\sin\theta\) equals
The largest interval lying in \(\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)\) for which \( f(x) = 4^{-x^2} + \cos^{-1}\left(\dfrac{x}{2}-1\right) + \log(\cos x) \) is defined, is:
If \( \sin^{-1}\dfrac{x}{5} + \sin^{-1}\dfrac{4}{5} = \dfrac{\pi}{2} \), then \( x \) equals:
We have ABC is a triangular park with AB = AC = 100 meters. M is the midpoint of BC and let the height of tower PM be \(h\) meters. If \(\cot\alpha = 3\sqrt{2}\) (where \(\alpha\) is the angle of elevation of P from A) and \(\cosec\beta = 2\sqrt{2}\) (where \(\beta\) is the angle of elevation of P from B), find \(h\) (in meters).
Given two poles ED = 5 m and CB = 10 m, ∠BAC = 15°. Find the distance DB (in meters).
The value of \(\sin^{-1}\left(\dfrac{12}{13}\right) - \sin^{-1}\left(\dfrac{3}{5}\right)\) is equal to:
A vertical pole MN is standing at a point N on the ground. A, B, C are three points on the ground such that N lies on segment AC. If angles of elevation of the top M of the pole from A, B, C are 30°, 45° and 65° respectively, then \(AB : BC\) equals
For any \(\theta \in \left(\frac{\pi}{4}, \frac{\pi}{2}\right)\), the expression \(3(\sin\theta - \cos\theta)^4 + 6(\sin\theta + \cos\theta)^2 + 4\sin^6\theta\) equals:
\(PQR\) is a triangular park with \(PQ = PR = 200\) m. A TV tower stands at the mid-point of \(QR\). If the angles of elevation of the top of the tower at \(P\), \(Q\) and \(R\) are, respectively, 45°, 30° and 30°, then the height of the tower (in m) is:
Given \(\sin^2 2\theta + \cos^4 2\theta = \dfrac{3}{4}\), find the sum of all values of \(\theta \in \left[0, \dfrac{\pi}{2}\right]\).
The equation \(e^{\sin x} - e^{-\sin x} - 4 = 0\) has
An aeroplane flying at a constant speed, parallel to the horizontal ground, \(\sqrt{3}\) km above it, is observed at an elevation of 60° from a point on the ground. If, after five seconds, its elevation from the same point is 30°, then the speed (in km h⁻¹) of the aeroplane is
Find the value of \(\cot^{-1}\left[\cot\left(\dfrac{\pi}{12} + \dfrac{\pi}{6} + \dfrac{\pi}{4}\right)\right]\) in degrees.
In triangle ABC, a : b : c = (1 + x) : 1 : (1 − x) where \(x \in (0,1)\). If \(\angle A = \frac{\pi}{2} + \angle C\), then \(12x^2\) is equal to
The value of $\displaystyle\sum_{r=2}^{\infty} \cot^{-1}(r^2 - 5r + 7)$ is
If $a=2$, then the sum of the infinite series $\cot^{-1}(2a^{-1}+a)+\cot^{-1}(2a^{-1}+3a)+\cot^{-1}(2a^{-1}+6a)+\cot^{-1}(2a^{-1}+10a)+\cdots$ is
Domain of \(f(x)=\log_e(\cos^{-1}\{\sqrt{x}\})\) where \(\{\cdot\}\) denotes fractional part:
Let set $A$ denote the solutions of $\cos^{-1}(4x^3-3x)=\tan^{-1}\!\left(\dfrac{2x}{1-x^2}\right)$. Then
The value of \(\cos^{-1}\cos\frac{2\pi}{3} - \cos^{-1}\frac{2}{3}\) is equal to
Question nos. 687 to 689Column-1 represents a condition to form trigonometric equation. Column-2 represents the value of \(\sin\theta + \cos\theta\) and Column-3 represents the general value of \(\theta\) satisfying the trigonometric equation.Column-1Column-2Column-3(I) If \(2^{\sin\theta}\), \(\sqrt{2}\) and \(2^{\cos\theta}\) are three terms of a decreasing G.P.(i) \(\dfrac{\sqrt{3}+1}{2}\)(P) \(\theta = 2n\pi - \dfrac{\pi}{2}\)(II) If \(\cos\theta\), \(\sec\theta\) and \(\cot\theta\) are three positive numbers in H.P.(ii) \(\sqrt{2}\)(Q) \(\theta = 2n\pi + \dfrac{\pi}{6}\)(III) If \(2\log\sec\theta\), \(\log 2\) and \(2\log\text{cosec}\,\theta\) are in A.P.(iii) \(-1\)(R) \(\theta = 2n\pi + \dfrac{\pi}{2}\)(IV) If G.M. of \((2+\sin\theta)\), \((3+\sin\theta)\) and \((4+\sin\theta)\) is equal to cube root of 6.(iv) \(1\)(S) \(\theta = 2n\pi + \dfrac{\pi}{4}\)689. Which of the following options is the only correct combination?
If \(\alpha = \theta_1 + \theta_2\) and \(x = \theta_1 - \theta_2\) and \(\tan\theta_1 = \lambda\tan\theta_2\), then \(\sin x : \sin\alpha\) is equal to
A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point \(O\) on the ground is 45°. It flies off horizontally straight away from the point \(O\). After one second, the elevation of the bird from \(O\) is reduced to 30°. Then the speed (in m/s) of the bird is