Trigonometry Questions (1127)

If the sum of values of $\theta$ in $(-3\pi, 3\pi)$ satisfying $\displaystyle\sum_{m=1}^{15}\sec\!\left(\theta+(m-1)\frac{\pi}{18}\right)\sec\!\left(\theta+m\frac{\pi}{18}\right)=(4+2\sqrt{3})\csc\frac{\pi}{18}$ is $\dfrac{k\pi}{10}$, then the value of $k$ is
We have ABC is a triangular park with AB = AC = 100 meters. M is the midpoint of BC and let the height of tower PM be \(h\) meters. If \(\cot\alpha = 3\sqrt{2}\) (where \(\alpha\) is the angle of elevation of P from A) and \(\cosec\beta = 2\sqrt{2}\) (where \(\beta\) is the angle of elevation of P from B), find \(h\) (in meters).
Given two poles ED = 5 m and CB = 10 m, ∠BAC = 15°. Find the distance DB (in meters).
The value of \(\sin^{-1}\left(\dfrac{12}{13}\right) - \sin^{-1}\left(\dfrac{3}{5}\right)\) is equal to:
A vertical pole MN is standing at a point N on the ground. A, B, C are three points on the ground such that N lies on segment AC. If angles of elevation of the top M of the pole from A, B, C are 30°, 45° and 65° respectively, then \(AB : BC\) equals
For any \(\theta \in \left(\frac{\pi}{4}, \frac{\pi}{2}\right)\), the expression \(3(\sin\theta - \cos\theta)^4 + 6(\sin\theta + \cos\theta)^2 + 4\sin^6\theta\) equals:
\(PQR\) is a triangular park with \(PQ = PR = 200\) m. A TV tower stands at the mid-point of \(QR\). If the angles of elevation of the top of the tower at \(P\), \(Q\) and \(R\) are, respectively, 45°, 30° and 30°, then the height of the tower (in m) is:
Given \(\sin^2 2\theta + \cos^4 2\theta = \dfrac{3}{4}\), find the sum of all values of \(\theta \in \left[0, \dfrac{\pi}{2}\right]\).
The exact value of $\text{cosec}\,10^\circ+\text{cosec}\,50^\circ-\text{cosec}\,70^\circ$ is
The equation \(e^{\sin x} - e^{-\sin x} - 4 = 0\) has
An aeroplane flying at a constant speed, parallel to the horizontal ground, \(\sqrt{3}\) km above it, is observed at an elevation of 60° from a point on the ground. If, after five seconds, its elevation from the same point is 30°, then the speed (in km h⁻¹) of the aeroplane is
Exhaustive value of $x$ such that $\cos^{-1}\left(\dfrac{8x}{1+16x^2}\right)=-\dfrac{\pi}{2}+2\tan^{-1}(4x)$
$x=\cos^{-1}(\cos 4)$, $y=\sin^{-1}(\sin 3)$, $z=\tan^{-1}(\tan 2)$, then $xyz=$
Find the value of \(\cot^{-1}\left[\cot\left(\dfrac{\pi}{12} + \dfrac{\pi}{6} + \dfrac{\pi}{4}\right)\right]\) in degrees.
In triangle ABC, a : b : c = (1 + x) : 1 : (1 − x) where \(x \in (0,1)\). If \(\angle A = \frac{\pi}{2} + \angle C\), then \(12x^2\) is equal to
The upper four-fifth portion of a vertical tower subtends an angle $\tan^{-1}\frac{8}{21}$ at a point $A$ in the horizontal plane through its foot and at a distance 50 m from the foot. If the angle subtended by the lower one fifth of tower at point $A$ is $\beta$, then the height of the tower can be
The value of $\displaystyle\sum_{r=2}^{\infty} \cot^{-1}(r^2 - 5r + 7)$ is
If $a=2$, then the sum of the infinite series $\cot^{-1}(2a^{-1}+a)+\cot^{-1}(2a^{-1}+3a)+\cot^{-1}(2a^{-1}+6a)+\cot^{-1}(2a^{-1}+10a)+\cdots$ is
Domain of \(f(x)=\log_e(\cos^{-1}\{\sqrt{x}\})\) where \(\{\cdot\}\) denotes fractional part:
Let set $A$ denote the solutions of $\cos^{-1}(4x^3-3x)=\tan^{-1}\!\left(\dfrac{2x}{1-x^2}\right)$. Then
The value of \(\cos^{-1}\cos\frac{2\pi}{3} - \cos^{-1}\frac{2}{3}\) is equal to
Question nos. 687 to 689Column-1 represents a condition to form trigonometric equation. Column-2 represents the value of \(\sin\theta + \cos\theta\) and Column-3 represents the general value of \(\theta\) satisfying the trigonometric equation.Column-1Column-2Column-3(I) If \(2^{\sin\theta}\), \(\sqrt{2}\) and \(2^{\cos\theta}\) are three terms of a decreasing G.P.(i) \(\dfrac{\sqrt{3}+1}{2}\)(P) \(\theta = 2n\pi - \dfrac{\pi}{2}\)(II) If \(\cos\theta\), \(\sec\theta\) and \(\cot\theta\) are three positive numbers in H.P.(ii) \(\sqrt{2}\)(Q) \(\theta = 2n\pi + \dfrac{\pi}{6}\)(III) If \(2\log\sec\theta\), \(\log 2\) and \(2\log\text{cosec}\,\theta\) are in A.P.(iii) \(-1\)(R) \(\theta = 2n\pi + \dfrac{\pi}{2}\)(IV) If G.M. of \((2+\sin\theta)\), \((3+\sin\theta)\) and \((4+\sin\theta)\) is equal to cube root of 6.(iv) \(1\)(S) \(\theta = 2n\pi + \dfrac{\pi}{4}\)689. Which of the following options is the only correct combination?
The general solution of $\cos 2\theta\cos\left(\dfrac{\theta}{2}\right)=\cos\left(\dfrac{3\theta}{2}\right)$ is
If a root of the equation $n^2\sin^2 x - 2\sin x - (2n+1) = 0$ lies in $\left[\dfrac{\pi}{2}, \pi\right]$, then the minimum positive integer value of $n$ is
In $\triangle ABC$, $\angle A = \tan^{-1}7$, $\angle C = \tan^{-1}\frac{4}{3}$. Let $D$ be an interior point on side $AC$ such that area of $\triangle ABD$ is twice the area of $\triangle BCD$. If $\angle ABD = \theta$, then the value of $\tan 2\theta$ is
If \(\alpha = \theta_1 + \theta_2\) and \(x = \theta_1 - \theta_2\) and \(\tan\theta_1 = \lambda\tan\theta_2\), then \(\sin x : \sin\alpha\) is equal to
A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point \(O\) on the ground is 45°. It flies off horizontally straight away from the point \(O\). After one second, the elevation of the bird from \(O\) is reduced to 30°. Then the speed (in m/s) of the bird is