Limits, Continuity & Differentiability Questions (1044)

Let \(f(x)\) be a continuous and differentiable function such that \(\displaystyle\lim_{h \to 0} \frac{f(3+7h) - f(3+4h)}{h} = 4\). Then the value of \(f'(3)\) equals:
\(\lim_{x \to 2} \dfrac{\sqrt{2\sin^2(x-2)}}{x-2}\)
$\dfrac{d}{dx}\left[\tan^{-1}\\!\left(\dfrac{\sqrt{2-x}}{1+x^2}\right)\right]$ equals $(x \ge 0)$:
Find \(a\), \(b\) and \(c\) such that \[\lim_{x \to 0} \frac{ax e^x - b\log(1+x) + cx e^{-x}}{x^2 \sin x} = 2\]
Let $f(x) = x + \sin x$. Suppose $g$ denotes the inverse function of $f$. The value of $g'\\!\left(\frac{\pi}{4} + \frac{1}{\sqrt{2}}\right)$ has the value equal to:
If $y = x + e^x$, then $\dfrac{d^2x}{dy^2}$ is:
If \(y = 1 + \dfrac{c_1}{x - c_1} + \dfrac{c_2 x}{(x - c_1)(x - c_2)} + \dfrac{c_3 x^2}{(x - c_1)(x - c_2)(x - c_3)}\), then \(\dfrac{dy}{dx}\) is equal to:
Let \(f(x) = ax^4 + bx^3 + cx^2 + dx + e\). If \(\displaystyle\lim_{x \to 0}\left(\dfrac{f(x)}{x^2} + 1\right) = 3\), \(f'(1) = 0\) and \(f'(2) = 0\), then the value of \(a\) is:
Given that \(f(a) = g(a) = k\); \(f^n(a) \neq g^n(a)\) for some \(n \in \mathbb{N}\) and \[\lim_{x \to a} \frac{f(a)\cdot g(x) - f(a) - g(a)f(x) + g(a)}{g(x) - f(x)} = 4\] Find the value of \(k\).
Let \( f: (-1, 1) \to R \) be a differentiable function with \( f(0) = -1 \) and \( f'(0) = 1 \). Let \( g(x) = [f(2f(x)+2)]^2 \). Then \( g'(0) = \)
\(f(x)=[\sin x]+\sqrt{\sin x-[\sin x]}\), where [.] is GIF. \(f(x)\) is:
\(f:\mathbb{R}\to\mathbb{R}\), \(g(x)=|f(x)|\). Which are NOT always true?
Let f and g be two functions such that g(f(x)) is defined. If f is differentiable at x and g is differentiable at f(x), then find the value of \(7g'(2\pi) + 3g''(2\pi)\), given that \(f'\!\left(\dfrac{3\pi}{2}\right) = \dfrac{1}{3}\) and \(f''\!\left(\dfrac{3\pi}{2}\right) = 0\).
If $f(4x) = 4f(x)$ for all $x$ and $f'(1)=2$, then $\displaystyle\lim_{x\to 1}\frac{\sqrt{f(x)}-\sqrt{f(1)}}{\sqrt{x}-1}$ is equal to:
If $2y = \cot^{-1}\!\left(\sqrt{\dfrac{\sqrt{3}\cos x + \sin x}{\sqrt{3}\cos x - \sin x}}\right)$, then $\dfrac{dy}{dx}$ is equal to:
If \(f(x) = \{x + \sin x\} + [x - \sin x] + [x]\) where \([y]\) and \(\{y\}\) denote greatest integer function and fractional part function of \(y\) respectively, then find the number of points of discontinuity in \([0, \pi]\).
If \(f(x) = \log_{\sec x} |\cos 4x| + |\sin x|\), then find \(\frac{dy}{dx}\) at \(x = -\frac{\pi}{6}\) from the first principle.
tignum function \(\text{tgn}(x)=\begin{cases}1 & [x]\text{ even}\\ -1 & [x]\text{ odd}\end{cases}\). \(f(x)=\text{tgn}(x)\cdot\sin(x)\cdot|x|\). Points of discontinuity in \([0,10]\):
limt→0(11/ sin2 t + · · · + n1/ sin2 t)sin2 t
If \(\lim_{x \to 0} \frac{x(1 + m\cos x) - n\sin x}{x^3} = 1\) then \(m =\) ______, \(n =\) ______
We have \(|f(x) - f(y)| \leq (x-y)^2\) for all \(x, y \in \mathbb{R}\) and \(f(0) = 0\). Find \(f(1)\).
The value of \( p \) and \( q \) for which the function \[ f(x) = \begin{cases} \dfrac{\sin(p+1)x + \sin x}{x}, & x 0 \end{cases} \] is continuous for all \( x \) in \( R \), is
If $f(x) = (2x-3x^2)^4 + \cos x$ and $g$ is the inverse of $f$, then which of the following is/are correct?
Let \(f(a) = g(a) = k\) and their \(n\)th derivatives \(f^n(a)\), \(g^n(a)\) exist and are not equal for some \(n\). Further, if \(\lim_{x \to a} \dfrac{f(a)g(x) - f(a) - g(a)f(x) + g(a)}{g(x) - f(x)} = 4\), then the value of \(k\) is
Given \(f(x) = 5 - |x - 2|\), graph of \(y = f(x)\) is as shown. So, \(f(x)\) is maximum at \(x = 2\), \(\alpha = 2\). Given \(g(x) = |x + 1|\), graph of \(y = g(x)\) is as shown. So, \(g(x)\) is minimum at \(x = -1\), \(\beta = -1\). Therefore, find \(\displaystyle\lim_{x \to -\alpha\beta} \frac{(x-1)(x^2 - 5x + 6)}{x^2 - 6x + 8}\).
Evaluate \(\lim_{x \to 0} \dfrac{\sqrt[3]{8+x} - \sqrt[3]{8+x^2-x^2}}{\sqrt[3]{8+x} - \sqrt[3]{8+x^2-x^2}}\)Evaluate \(\lim_{x \to 0} \dfrac{\sqrt{8+x} - \sqrt[3]{8+x^2} - x^2}{\sqrt[3]{8+x} - \sqrt[3]{8+x^2-x^2}}\)
If \(a_1 = 1\) and \(a_n = n(1 + a_{n-1})\) \(\forall\, n \geq 2\), and \(L = \lim_{n \to \infty}\left(1 + \dfrac{1}{a_1}\right)\left(1 + \dfrac{1}{a_2}\right)\cdots\left(1 + \dfrac{1}{a_n}\right)\), then
\(f(x+y)+f(x-y)=2f(x)\ \forall x,y\in\mathbb{R}\), \(f(0)=0\) and \(f\) is differentiable. Which are correct?
If \(x = 3\tan t\) and \(y = 3\sec t\), then the value of \(\dfrac{d^2y}{dx^2}\) at \(t = \dfrac{\pi}{4}\), is:
If $(\cos x)^y = (\sin y)^x$, then $\dfrac{dy}{dx}$ equals:
Let $g$ be the inverse of $f$. If $f(x)=x^2+3x-3$ (for appropriate domain) and $g(7)=1$, find the value of $g'(7)$. (Express as lowest fraction; if $p/q$, give $p+q$; answer 2 from key means $g'(7)=1/5$ giving $p+q=6$... or $g'(7)=2$).
Let \(f\) be differentiable at \(x=0\) and \(f'(0)=1\). Then \(\lim_{h\to 0}\dfrac{f(h)-f(-2h)}{h}=\)
\(\lim_{x \to 0} \dfrac{e^{x^2} - \cos x}{\sin^2 x}\)
Let A = \[ A = \lim_{x \to 0} \frac{2^{\tan x} - 2^{\sin x}}{x^3} \] Find the value of \(e^{4A}\).
\( \dfrac{d^2x}{dy^2} \) equals
If \(\lim_{x\to 0}\dfrac{1-\cos\left(1-\cos\frac{x}{2}\right)}{2^m x^n}\) equals the left hand derivative of \(e^{-|x|}\) at \(x=0\), find |n+2m| divisible by?
If \(x^2 + y^2 + \sin y = 4\), then the value of \(\dfrac{d^2y}{dx^2}\) at the point \((-2, 0)\) is
If \(t = e^{x^2}\) and \(y = t^2 - 1\) then \(\left(\dfrac{dy}{dx}\right)_{x=1}\) is
Let \(f:\mathbb{R}\to\mathbb{R}\) be differentiable with \(|f(x)-f(y)|\le|x-y|^3\) for all \(x,y\in\mathbb{R}\). If \(f(10)=100\), then \(f(20)=\)
Graph of \(f(x)\) shown (piecewise linear on [0,5] with values f(0)=1, f(1)=1, f(2)=2, f(3)=2, f(4)=2, f(5)=2 approximately). Which are correct?
Given that \(f(x) \geq 0\) and continuous \(\forall x \in \mathbb{R}\), and \(A = \int_{\pi/4}^{\beta} f(x)\, dx = \left(\beta \sin\beta + \dfrac{\pi}{4}\cos\beta + \sqrt{2}\right)\beta\), \(\beta > \dfrac{\pi}{4}\). Find \(f\left(\dfrac{\pi}{2}\right)\).
The value of \(\lim_{x \to 0^+} \dfrac{\displaystyle\int_0^{\arctan x} \sin t^2\, dt}{x\cos x - x}\) is equal to:
If \(y = \left[x + \sqrt{x^2-1}\right]^{15} + \left[x - \sqrt{x^2-1}\right]^{15}\), then \((x^2-1)\dfrac{d^2y}{dx^2} + x\dfrac{dy}{dx}\) is equal to
Let \(f(x) = 5 - |x - 2|\) and \(g(x) = |x + 1|\), \(x \in R\). If \(f(x)\) attains maximum value at \(\alpha\) and \(g(x)\) attains minimum value at \(\beta\), then \(\lim_{x \to -\alpha\beta} \dfrac{(x-1)(x^2 - 5x + 6)}{x^2 - 6x + 8}\) is equal to
Let K be the set of all real values of x where the function \( f(x) = \sin|x| - |x| + 2(x - \pi)\cos|x| \) is not differentiable. Then the set K is equal to:
Let \(f(x)\) be a differentiable function in \([-1, \infty)\) and \(f(0) = 1\) such that \(\lim_{t \to x+1} \frac{t^2 f(x+1) - (x+1)^2 f(t)}{f(t) - f(x+1)} = 1\). Find the value of \(\lim_{x \to 1} \frac{\ln(f(x)) - \ln 2}{x-1}\).
Which statements are correct?(A) ∃ f:[0,1]→ℝ discontinuous everywhere with |f| continuous everywhere(B) F=f·g, f diff at x=a, f(a)=0, g continuous at x=a ⟹ F diff at x=a(C) Rf'(a)=2, Lf'(a)=3 ⟹ f non-diff at x=a but always continuous(D) f(a) and f(b) have opposite signs ⟹ ∃ solution of f(x)=0 in (a,b) if f continuous on [a,b]
If the function \(f\) defined on \(\left(\dfrac{\pi}{6},\,\dfrac{\pi}{3}\right)\) by \[f(x) = \begin{cases} \dfrac{\sqrt{2}\cos x - 1}{\cot x - 1}, & x \neq \dfrac{\pi}{4} \\ k, & x = \dfrac{\pi}{4} \end{cases}\] is continuous, then \(k\) is equal to:
Without expansion or using L'Hospital's rule, prove that \(\lim_{\theta \to 0} \dfrac{3\theta - \sin 3\theta}{\theta^3} = \dfrac{1}{6}\).
If $y = (x^2+2x)(3x^4+4x^3)$, find the number of zeros of $y'$ in $(0,\infty)$.