Given \(f(x) = 5 - |x - 2|\), graph of \(y = f(x)\) is as shown. So, \(f(x)\) is maximum at \(x = 2\), \(\alpha = 2\). Given \(g(x) = |x + 1|\), graph of \(y = g(x)\) is as shown. So, \(g(x)\) is minimum at \(x = -1\), \(\beta = -1\). Therefore, find \(\displaystyle\lim_{x \to -\alpha\beta} \frac{(x-1)(x^2 - 5x + 6)}{x^2 - 6x + 8}\).